All categories

3 years ago

Can the law of sines be used to solve the triangle

Mathematics

1 answer:

ivanzaharov [21]3 years ago

8 0

Answer:

Step-by-step explanation:

No, the law of sines cannot be used to solve the triangle. The triangle shows the measures of two sides and an included angle. To use the law of sines, you need to know the measure of an angle and its opposite side.

Answer On Edg. 2020

You might be interested in

Tlachihualtepeti is a pyramid in mexico. each side of the base measures 450 meters and had an original height of 66 meters. How

storchak [24]

Answer:

Basically, we are to determine the volume of that pyramid.

Right Regular Pyramid Volume = (Area of the Base * Height) ÷ 3

Volume = (202,500 * 66) ÷ 3

Volume = 4,455,000 cubic meters

By the way Wikipedia says that is the largest pyramid in the world.

Step-by-step explanation:

3 0

2 years ago

Slope = 4, passing through (-6, 8)

Mademuasel [1]

The point slope form is y - 8 = 4(x + 6) and the slope intercept form would be y = 4x + 32.

In order to find this, we'll start with the base form of point-slope form.

y - y1 = m(x - x1) ----> Plug in the numbers

y - 8 = 4(x - -6) ----> Simplify

y - 8 = 4(x + 6)

Now to find slope intercept form, solve for y.

y - 8 = 4(x + 6) ----> distribute the 4

y - 8 = 4x + 24 -----> add 8 to both sides

y = 4x + 32

7 0

2 years ago

How is dividing decimals different from dividing whole numbers?Please answer immediately.

Masteriza [31]

If you divide decimals you have to bring up the decimal point but if you divide whole numbers you dont have any decimal points so you just divide the numbers. Sorry if i didnt help i just wanted to help.

7 0

3 years ago

Read 2 more answers

Find the area and perimeter of the shape below. Help plzzz.

kozerog [31]

Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²

4 0

3 years ago

On a snow day, Mason created two snowmen in his backyard. Snowman A was built to a height of 51 inches and Snowman B was built t

mr_godi [17]

Answer:

A ( t ) = -4t + 51

B ( t ) = -2t + 29

t < 11 hours ... [ 0 , 11 ]

Step-by-step explanation:

Given:-

- The height of snowman A, Ao = 51 in

- The height of snowman B, Bo = 29 in

Solution:-

- The day Mason made two snowmans ( A and B ) with their respective heights ( A(t) and B(t) ) will be considered as the initial value of the following ordinary differential equation.

- To construct two first order Linear ODEs we will consider the rate of change in heights of each snowman from the following day.

- The rate of change of snowman A's height ( A ) is:

$\frac{d h_a}{dt} = -4$

- The rate of change of snowman B's height ( B ) is:

$\frac{d h_b}{dt} = -2$

Where,

t: The time in hours from the start of melting process.

- We will separate the variables and integrate both of the ODEs as follows:

$\int {} \, dA= -4 * \int {} \, dt + c\\\\A ( t ) = -4t + c$

$\int {} \, dB= -2 * \int {} \, dt + c\\\\B ( t ) = -2t + c$

- Evaluate the constant of integration ( c ) for each solution to ODE using the initial values given: A ( 0 ) = Ao = 51 in and B ( 0 ) = Bo = 29 in:

$A ( 0 ) = -4(0) + c = 51\\\\c = 51$

$B ( 0 ) = -2(0) + c = 29\\\\c = 29$

- The solution to the differential equations are as follows:

A ( t ) = -4t + 51

B ( t ) = -2t + 29

- To determine the time domain over which the snowman A height A ( t ) is greater than snowman B height B ( t ). We will set up an inequality as follows:

A ( t ) > B ( t )

-4t + 51 > -2t + 29

2t < 22

t < 11 hours

- The time domain over which snowman A' height is greater than snowman B' height is given by the following notation:

Answer: [ 0 , 11 ]

8 0

2 years ago