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MrMuchimi
3 years ago
9

Name the quadrant in which the angle θ lies. cos θ < 0 , csc θ < 0

Mathematics
1 answer:
IgorC [24]3 years ago
4 0
It is the second quadrant. 
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Answer this for 35 points, brainliest, a heart and more
coldgirl [10]

Answer:

7. multiply 2

8. multiply 5 (i think)

9. y=12/ x=4

x/y=3

10. $100

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If y&gt;0, which of these values of x is NOT in the domain of this equation? y=x2+7x
alisha [4.7K]

Answer:

\boxed{\sf \ \ \  [-7,0] \ \ \ }

Step-by-step explanation:

Hello

y=x^2+7x=x(x+7) >0\\ x>0 \ and \ x+7 >0 \ \ or \ \ x

So values of x which is not in this domain is

-7\leq x\leq 0

which is [-7,0]

hope this helps

6 0
4 years ago
How to rewrite equations in standard form
Shalnov [3]
Standard form is Ax+By=C
5 0
3 years ago
Find the point at which the line with parametric equations x = 2 3t, y =-4t, z =5 t intersects the plane 4x 5y -2z=18
sashaice [31]

It looks like you have

\begin{cases}x=2+3t\\y=-4t\\z=5+t\end{cases}

Substituting these in to the plane equation, we have

4x+5y-2z = 4(2+3t) + 5(-4t) - 2(5+t) = -2-10t = 18 \\\\ \implies-10t = 20 \implies t = -2

When t=-2, we get the point

\begin{cases}x=2+3(-2)\\y=-4(-2)\\z=5+(-2)\end{cases} \implies (x,y,z) = \boxed{(-4,8,3)}

4 0
2 years ago
Jenna spends $15.04 at the store on notebooks and folders for school. Notebooks cost $4.85 each, and folders cost $0.89 each. Sh
cluponka [151]

Answer:

\boxed{\text{2 notebooks and 6 folders}}

Step-by-step explanation:

Let n = number of notebooks

and f = number of fodders

You have a system of two equations:

\begin{cases}(1)& 4.85n + 0.89f = 15.04\\(2) & n+ f = 8\end{cases}\\\\

\begin{array}{lrcll}(3) & f & = & 8-n &\text{Subtracted n from each side of (2)}\\& 4.85n+0.89(8-n) & = & 15.04 &\text{Substituted (3) into (1)}\\& 4.85n+7.12-0.89n & = & 15.04 &\text{Distributed 0.89}\\& 3.96n+7.12 & = & 15.04 &\text{Combined like terms} \\& 3.96n & = & 7.92 & \text{Subtracted 7.12 from each side} \\(4) & n & = & 2 & \text{Divided each side by 3.96}\\& 2+ f & = & 8 & \text{Substituted (4) into (2)}\\& f & = & 6 &\text{Subtracted 2 from each side} \\\end{array}

Jenna bought \boxed{\textbf{two notebooks and six folders} }.

Check:

\begin{array}{rclcrcl}4.85\times2+0.89\times6 & =& 15.04 & \qquad &2+6&=&8\\9.70+5.34 & = & 15.04 & \qquad &8&=&8\\15.04& = & 15.04 & & & & \\\end{array}

OK.

4 0
3 years ago
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