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2 years ago

Luke puts $35 in his savings account every month. Use a calculator to find how much money he will save in a year.

Mathematics

2 answers:

irakobra [83]2 years ago

8 0

So if he Puts 35$ every Month for 12 months Is 35x12 = 420 for A year

olganol [36]2 years ago

4 0

u put 35*12 in the calculator and it will give u 420

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How do you do this and what’s the answer to this I been stuck on this question for litterly 20 mins

Vsevolod [243]

$\bf T=2\pi \sqrt{\cfrac{L}{g}}\implies \stackrel{\textit{squaring both sides}}{(T)^2=\left( 2\pi \sqrt{\cfrac{L}{g}}\ \right)^2}\implies T^2=2^2\pi^2\sqrt{\left( \cfrac{L}{g} \right)^2} \\\\\\ T^2=4\pi^2\cfrac{L}{g}\implies T^2=\cfrac{4\pi^2L}{g}\implies gT^2=4\pi^2L\implies g=\cfrac{4\pi^2L}{T^2}$

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3 years ago

A rectangular photo frame covers an area of 20 square inches on a wall. The width of the frame is 1 inch less than its length. F

Salsk061 [2.6K]

You need to find two factors of 20 that are consecutive: 4,5.
Answer: 5inx4in

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3 years ago

Given an acceleration vector, initial velocity u0,v0,w0 , and initial position x0,y0,z0 , find the velocity and position vectors

dsp73

Answer:

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

Step-by-step explanation:

given that acceleration vector is a funciton of time and at time t

$a(t) = (5,5t, 8t)$

v(t) can be obtained by integrating a(t)

v(t) = $(5t, 5t^2/2, 4t^2)+(u_0,v_0,w_0)\\=(5t+15, 5t^2/2, 4t^2)$

Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.

The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)

Position vector can be obtained by integrating v(t)

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

5 0

2 years ago

Partial fraction decomposition<br> 20x+9/25x^2+20x+4

ozzi

Step-by-step explanation:

We have

$\frac{20x + 9}{25 {x}^{2} + 20x + 4 }$

Let's factor the denomiator first,

the denomaitor is a perfect square so we get

$\frac{20x + 9}{(5x + 2) {}^{2} }$

Now, we must think of two fractions that

$\frac{a}{(5x + 2) {}^{2} } + \frac{b}{5x + 2}$

We use a perfect square term for one fraction, then a linear one for the next, because if we set both of the denomiator to the same factor, we would get a inconsistent system.

So right now, we have

$\frac{a}{(5x + 2) { }^{2} } + \frac{b}{5x + 2} = \frac{20x +9 }{25 {x}^{2} + 20x + 4 }$