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stira [4]
3 years ago
8

Which of the following would be the x-intercept and y-intercept of a line that is perpendicular to the line 3x+6y=0

Mathematics
1 answer:
Artist 52 [7]3 years ago
5 0

Answer:

x-intercept : (0,0)

y-intercept : (0,0)

Step-by-step explanation: To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

Hope this helps you out! ☺

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Why is it impossible to list the set of rational numbers using the roster method?
dsp73
It is impossible to list the set of rational numbers using the roster method because the set of rational numbers is uncountable/inumerable.

There is no way to list all the members of the set of rational numbers.
5 0
3 years ago
I need to know if the answer to number 9. Is correct
slava [35]
The answer to number 9 would be 43. 

Since it tells you that there is a straight angle that would equal 180. So I added up 61 30 and 46. I got 137. Then subtracted 137 from 180 and got 43.
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac15%20%284%20-%203x%29%20%3D%5Cfrac15%20%283x%20-%204%29" id="TexFormula1" title="\frac1
emmainna [20.7K]

Answer:

x=4/3

Step-by-step explanation:

In pic

(hope this helps can I pls have brainlist (crown) ☺️)

8 0
2 years ago
Read 2 more answers
Explain how you can find the missing number in 3 4/5 / missing number = 2 5/7
hram777 [196]
Cause you have the slashes and 2/4/5/6/7and 3/4/5/6/7
3 0
3 years ago
Whats the center and radius of (x+3)^2+(y-5)^2=64
Alexandra [31]

Answer:

The answer to your question is Center = (-3, 5)  radius = 8

Step-by-step explanation:

Data

                (x + 3)²  +  (y - 5)² = 64

Process

Because of the characteristics of the equation, we conclude that it is a circle.

Standard form of a circle:

              (x - h)² + (y - k)² = r²

In this form of the equation, the center has coordinates (h, k), just change the signs.

And to get the radius, just get the square root of r²

h = -3

k = 5

r = 8

Center = (-3, 5)

radius = 8

5 0
3 years ago
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