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3 years ago

What is 6+5342 equal

Mathematics

2 answers:

ASHA 777 [7]3 years ago

5 0

5.348

this to weird, where is the trap?

zysi [14]3 years ago

3 0

Answer:

5,348

Hope this helps.

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A farmer has 191 sheep and a number of lambs

Svetllana [295]

19 sheep have 3 lambs each means 19x3=57 lamps
Plus
117 sheep have 2 lambs each means 117x2=234 Lamps
Plus
All the other sheep have 1 lamb each means (191-19-117)=55
Equal:
19x3+117x2+(191-19-117)=57+234+55=346 Lamps

8 0

4 years ago

Read 2 more answers

Round 0.0851 to the nearest whole number

Nitella [24]

Answer:

Step-by-step explanation:

7 0

3 years ago

A cylindrical trash can is 30 inches high and has a base radius of 7 inches. What is the outside surface area of this trash can,

Paladinen [302]

Answer:

The answer to your question is: A = 1627.35 in²

Step-by-step explanation:

Data

height = 30 in

radius = 7 in

A = ?

Lateral area

A = 2πrh

A = 2(3.1416)(7)(30) = 1319.47 in²

Area of the base and lid

A = 2 x πr² = 2(3.1416)(7)²

= 307.88 in²

At = 1319.47 in² + 307.88 in² = 1627.35 in²

5 0

4 years ago

Rachna borrowed a certain sum at the rate of 15% per annum. if she paid at the end of the two years Rs.1290 as interest Compound

Natalija [7]

Given info:

Compound Interest = Rs.1290

Rate of Interest = 15% p.a

Time = 2 years

<h3>Formula we have to know:-</h3>

$\dag{\underline{\boxed{\sf{C.I = P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1}}}}$

Where

C.I = Compound Interest

P = Principle

R = Rate of Interest

N = Time

$\textsf{ \underline{Solution-}}\\$

Here

C.I = Rs.1290

R = 15%

N = 2 years

Principle = ?

Now,Calculating the sum (Principle) borrowed by Rachna

$\quad{: \implies{\sf{C.I = \Bigg[P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1 \Bigg]}}}$

Substituting the given values

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(1 + \dfrac{15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{(1 \times 100) + 15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \times \dfrac{115}{100} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{13225}{10000} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg( \cancel{\dfrac{13225}{10000}} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg({1.3225 - 1} \bigg) \Bigg]}}}$

$\quad{: \implies{\sf{1290 = P \times {0.3225}}}}$

$\quad{: \implies{\sf{\dfrac{1290}{0.3225} = P}}}$

$\quad{: \implies{\sf{\dfrac{1290 \times 1000}{0.3225 \times 1000} = P}}}$

$\quad{: \implies{\sf{\dfrac{12900000}{3225} = P}}}$

$\quad{: \implies{\sf{\cancel{\dfrac{12900000}{3225}} = P}}}$

$\quad{: \implies{\sf{Rs.4000 = P}}}$

$\quad{\dag{\underline{\boxed{\tt{\blue{Principle} = \purple{Rs.4000 }}}}}}$

$\begin{gathered}\end{gathered}$

Hence,

The sum (Principle) is Rs.4000.

3 0

3 years ago

During the summer, Mr. Brust does a lot of napping (and snoring)! In a typical nap, Mr. Brust will snore on average 320 times (o

Komok [63]

Answer: Mr Brust snored a total of 19,840 times last summer

Step-by-step explanation:

Mr Brust snores in the ratio of 1 nap : 320 snores or 1 nap = 320 snores

Given that he took a nap everyday, last summer We have that .

For the month of July,

he had 31 naps( 31 days are in July)

Number of snores he made =31 x 320=9,920 snores

For the month of August

he also took 31 naps ( 31 days are in AugusT)

Number of snores he made = 31 x 320=9,920 snores

Therefore Mr Brust snored a total of 9,920+ 9,920 =19,840 times

8 0

3 years ago