Answer: P = 84m and A = 441m^2
Explanation:
Find Perimeter:
Form: P = 4a
But a = 21m
=> P = 4 x 21
=> P = 84m
Find Area:
Form: A = a • a
But a = 21m
=> A = 21 • 21
=> A = 441m^2
Answer:
I believe it's B,hope this helps! :)
Option C:
,
is the asymptotes of the equation.
Explanation:
The equation is ![f(x)=\frac{2x}{x+4}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B2x%7D%7Bx%2B4%7D)
The vertical asymptote of the equation can be determined by equating the denominator of the equation to zero.
Thus, we have,
![x+4=0](https://tex.z-dn.net/?f=x%2B4%3D0)
![x=-4](https://tex.z-dn.net/?f=x%3D-4)
Hence, the vertical asymptote of the function is ![x=-4](https://tex.z-dn.net/?f=x%3D-4)
Now, we shall determine the horizontal asymptote.
The horizontal asymptote of the function can be determined by dividing the leading coefficient of x in the numerator by the leading coefficient of x in the denominator.
Thus, we have,
![y=\frac{2}{1}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B1%7D)
![y=2](https://tex.z-dn.net/?f=y%3D2)
Hence, the horizontal asymptote of the function is ![y=2](https://tex.z-dn.net/?f=y%3D2)
Therefore, Option C is the correct answer.
Answer:
10 km
Step-by-step explanation:
<em>Distance = 5 cm</em>
<em>4 cm = 8 km</em>
<em>In km, how far apart is school and home?</em>
Cross Multiply
· ![\frac{5cm}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B5cm%7D%7B1%7D)
Cancel centimeters
![\frac{40(km)(cm)}{4cm}](https://tex.z-dn.net/?f=%5Cfrac%7B40%28km%29%28cm%29%7D%7B4cm%7D)
Divide
= ![\frac{40km}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B40km%7D%7B4%7D)
= 10 km
Answer:
Bill launched a model rocket, and estimated its height h, In feet, after 1 seconds. His results are shown in the table
Time, 1 0 1 2 3 4
Height, h 0 110 190 240 255
Bill's data can be modeled by the function h(t) = -1612 + 128.
Which value is the best prediction for the height of the rocket after 5.5 seconds?
A 150 ft
B. 180 ft
C. 220 ft
D. 250 ft
E 260 ft