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3 years ago

Question on exact area of a circle

Mathematics

2 answers:

Mama L [17]3 years ago

5 0

Same thing:
The area formula of a circle is:
A = r²

given is the diameter = 44 ft so the radius is
r =

Apply the formula
A = (22)²
= 484<span> ft²</span>

Answer is the second option, B. 484 <span>ft²</span>

dexar [7]3 years ago

4 0

Area: pi*222= 484*pi sqr ft

You might be interested in

The third term in a sequence is 25. The fifth term is 225. What are the possible values of the 4th term of the sequence if it is

balu736 [363]

Answer:

if it is arithmetic, ach item us increase linearly. The general term is - 175+100(n-1)

where n is the number of term.

the 4th term is 125

if it is geometic, each item us increased exponetially. T he general term is 25/9 x 3^(n-1)

where n is the number of term

the 4th term is 75

4 0

3 years ago

1) What is the equation of a line that is perpendicular to 2x+y=−4 and passes through the point (2, −8)

defon

$Let\ k:y=m_1x+b_1\ and\ l:y=m_2x+b_2,\ then\\\\l\ \perp\ k\iff m_1m_2=-1.\\\\\text{We have}\ k:2x+y=-4\qquad subtract\ 2x\ from\ both\ sides\\\\k:y=-2x-4\to m_1=-2\\\\l:y=mx+b\\\\l\ \perp\ k\iff-2m=-1\qquad divide\ both\ sides\ by\ (-2)\\\\m=\dfrac{1}{2}\\\\l:y=\dfrac{1}{2}x+b\\\\\text{The line}\ l\ \text{passes throuth the point (2, -8).}\\\text{Susbtitute the coordinates of the point to the equation of the line }\ l:\\\\-8=\dfrac{1}{2}(2)+b\\\\-8=1+b\qquad subtract\ 1\ from\ both\ sides\\\\-9=b\to b=-9$

$\boxed{y=\dfrac{1}{2}x-9}$

If ΔABC is a right triangle, then we can use Pythagorean theorem.

The formula of a length of a line segment AB:

$|AB|=\sqrt{(x_B-x_A)^2+(Y_B-y_A)^2}$

A(1, -1), B(3, 2)

$|AB|=\sqrt{(3-1)^2+(2-(-1))^2}=\sqrt{2^2+3^2}=\sqrt{4+9}=\sqrt{13}$

(1) C(0, 2)

$|AC|=\sqrt{(0-1)^2+(2-(-1))^2}=\sqrt{(-1)^2+3^2}=\sqrt{1+9}=\sqrt{10}\\\\|BC|=\sqrt{(0-3)^2+(2-2)^2}=\sqrt{(-3)^2+0^2}=\sqrt9=3$

$\sqrt{13} >\sqrt{10} > 3\\\\3^2+(\sqrt{10})^2\stackrel{?}{=} (\sqrt{13})^2\\\\L=9+10=19\\R=13\\L\neq R\\Not\ a\ Right\ Triangle$

(2) C(3, -1)

$|AC|=\sqrt{(3-1)^2+(-1-(-1))^2}=\sqrt{2^2+0^2}=\sqrt4=2\\\\|BC|=\sqrt{(3-3)^2+(-1-2)^2}=\sqrt{0^2+(-3)^2}=\sqrt9=3$

$\sqrt{13} > 3 > 2\\\\3^2+2^2\stackrel{?}{=}(\sqrt{13})^2\\\\L=9+4=13\\R=13\\L=R\\Right\ Triangle$

(3) C(0, 4)

$|AC|=\sqrt{(0-1)^2+(4-(-1))^2}=\sqrt{(-1)^2+5^2}=\sqrt{1+25}=\sqrt{26}\\\\|BC|=\sqrt{(0-3)^2+(4-2)^2}=\sqrt{(-3)^2+2^2}=\sqrt{9+4}=\sqrt{13}$

$\sqrt{26} > \sqrt{13}=\sqrt{13}\\\\(\sqrt{13})^2+(\sqrt{13})^2\stackrel{?}{=}(\sqrt{26})^2\\\\L=13+13=26\\R=26\\Right\ Triangle$

8 0

3 years ago

What is 9/8 squaredto the power of 2 ?

Julli [10]

The answer would be
1.265
Or
81/64

5 0

3 years ago

Read 2 more answers

According to a study conducted in one city, 35% of adults in the city have credit card debts more than $2.000. A simple random s

BabaBlast [244]

Answer:

Binomial; \mu p=87.5, \sigma p=7.542

Step-by-step explanation:

a distribution is said be a binomial distribution iff

The probability of success of that event( let it be p) is same for every trial
each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
there are fixed number of trials (n)
the trials are independent

here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)

here n=250

the probability of success(0.35) is same for every trial

(35/100=0.35 is the required p here)

$\mu_{p} =n*p=250*\frac{35}{100} =250*0.35=87.5$

[since, the formula for $\mu _{p} =n*p$ ]

$\sigma _{p} =\sqrt{n*(p)*(1-p)} = \sqrt{250*0.35*(1-0.35)} = 7.542 ( approximately)$

[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}

therefore, it is Binomial; \mu p=87.5, \sigma p=7.542

4 0

3 years ago

How could I write the fractions 8/100 3/5 and 7/10 from least to greatest?

iVinArrow [24]

Get them to have a common denominator. 100 is the common denominator, so change 7/10 and 3/5 to have a denominator of 100. 7/10=70/100 and 3/5=60/100. So from least to greatest it will go 8/100, 3/5, 7/10.

5 0

4 years ago

Read 2 more answers