Answer:
So estimate.
Really depends on what needs to be estimated, the answer or the overall equation.
So doing the real one first.
283/11 = 25 8/11
You can’t have “part” of a student so rounding this you can go up since 8 is more then half of 11
So 26 students
If you were to round the overall equation then you’d get
280 / 10 which is 28 students per class
So two options.
Answer:
The sample space is:
- (T,N): table height and brown
- (T, W): table height and white
- (T, K) : table height and black
- (B, N): bar height and brown
- (B, W): bar height and white
- (B, K): bar height and black
- (X, N): XL height and brown
- (X, W): XL height and white
- (W, K): XL height and black
Explanation:
The <em>sample space </em>is the set of all the possible outputs, i.e. the possible different combinations that can be choosen.
Use the letters T, B, and X to represent, respectively, table height, bar height, and XL height,
Use letters N, W, and K to represent, respectively, the colors brown, white and black.
Each combination consists of a height (T, B or X) and a color (N, W, K); thus, your sample space shall have 3 × 3 different combinations. These are:
- (T,N): table height and brown
- (T, W): table height and white
- (T, K) : table height and black
- (B, N): bar height and brown
- (B, W): bar height and white
- (B, K): bar height and black
- (X, N): XL height and brown
- (X, W): XL height and white
- (W, K): XL height and black
Answer:
She can make 34 bows with 10 feet of ribbon left
Step-by-step explanation:
1.5x34=51
61-51=10 feet of ribbons left
51/1.5=x
Answer:
{y≥1
,{y-x>0
Step-by-step explanation:
First of all you have to consider the shaded region. It is bound by two lines.
The first line is a solid line that cuts the y-axis at +1. it's equation is y = 1. since the shade region is on the upper side where y values increase, the unequivocally will be y≥1. notice that the sign ≥ is due to the solid line which indicates points on the solid line are part of the solution.
the second line is the broken line. it passes through the origin (0,0) and (1,1) any two points can be taken. the gradient is 1. m= (y1-y2)/(x1-x2) = (0-1)/(0-1)=(-1/-1)= 1. the equation of a straight line is
y=mx + c where m is gradient and c is the VA)ue of y as the line crosses the y axis ( y-intercept) which in this case is 0 at (0,0).so the equation will be y=1(x) + 0
y=x if we subtract x from both sides we have
y-x=0
since the shaded region is on the upper side as y-x increases the in equality will be
y-x>0 notice since the line is broken it shall be just > not≥ because points on a broken line are not included in the shaded region.