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Juliette [100K]
3 years ago
7

Can I have help on this

Computers and Technology
2 answers:
never [62]3 years ago
6 0

the answer is the seconf one


ValentinkaMS [17]3 years ago
3 0
It’s the second one (italics button
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Identify why research and a clearly written problem statement are important. Select all that apply. They result in a clear and c
saveliy_v [14]

Answer:

They result in a clear and concise statement of the problem

They ensure that all stakeholder needs are considered.

They result in a document that is easy to understand

Explanation:

Problem statement are very vital in research they are key notes that tells what the research is all about and solution it will provide. They are key notes to understand a research and the knowledge gap the research is filling.

Problem statement is a guide through which solution are measured, it gives a clear direction of what the research is all about.

Problem statement are usually easy to understand, they are written in ways that everyone who picks the paper up can understand why the research was conducted.

All this are why a problem statement is important.

7 0
2 years ago
Read 2 more answers
Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type
sattari [20]

Solution :

#include  $$

#include $$

#include $$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal$\text{To}$Binary(char* hexdec)

{

 

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$(sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

 

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0
2 years ago
The current standard for RFID is based off of Group of answer choices MIT standards IEEE standards ISO standards there is no agr
mamaluj [8]

Answer:

ISO standards

Explanation:

ISO / IEC 14443 is the ISO standard that covers RFID usage by devices.

EPCglobal - Electronics Product Code Global Incorporated is also another international standard that covers RFID. These two standards work together to standardize RFID products produced by manufacturers so that these products can be the same across different markets and manufacturers. Example I can purchase a tag from one manufacturer and a transceiver from another and they would function well together. There are also other standards for RFID but the above two are the biggest and most popular with ISO being the oldest.

4 0
2 years ago
Using truth table, prove that:<br><br> (A + B). C = (A . C)+ (B .C) ?
Genrish500 [490]

Answer:

The image of truth table is attached.

Explanation:

In the truth table there is a separate table for the expression (A+B).C and for the expression (A.C)+(B.C) you can see in the truth table that the columns of (A+B).C is having same values as the (A.C)+(B.C).Hence we can conclude that (A+B).C is equal to (A.C)+(B.C).

4 0
2 years ago
Public class Bird
Anna007 [38]

Answer:

Answer below.

Explanation:

You are creating an object of bird "b" with a talon strength of 5 and a beak of 5.

public Hawk(int talon, int beak)

{

super(beak);

talonStrength = talon;

}

Please mark brainliest if this is the answer you were looking for

Please mark brainliest if this is the answer you were looking for

6 0
2 years ago
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