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netineya [11]
3 years ago
14

which of the following sentences uses active voice?(answers to choose from are in the photo)-this is in my computer applications

class-

Computers and Technology
2 answers:
andrezito [222]3 years ago
6 0
Last week, Nate and I counted all the inventory. answer :A
kotegsom [21]3 years ago
6 0

option A)

Last week, Nate and I counted all the inventory.

all other choices are passive voices

this sentence follows a clear subject + verb + object construct that's why it is an active voice. In fact, sentences constructed in the active voice add impact to your writing. but on the other hand With passive voice, the subject is acted upon by the verb.


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Sam wants to move from his current role in his organization to a managerial role. Which certification will help him get on a man
jolli1 [7]

CCIE refers to Cisco Certified Internetwork Expert, a technical certification that demonstrates high proficiency of managing and establishing computer networks.

CSPM may refer to Certified Security Project Manager, which is a certification to demonstrate the individual’s capability in managing project in the field of cybersecurity.

MCITP refers to Microsoft Certified IT Professional, which demonstrates an individual’s ability to be a database or enterprise messaging administrator.

Oracle DBA refers to Oracle Database Administrator, and this certification demonstrates an individual’s ability to manage Oracle’s database from retrieving, maintaining, and editing them.

While PMP refers to Project Management Professional certification, one that you can use to prove your abilities as a project manager in various business contexts.  

Thus, the best certification for him to use to get to a managerial career path is PMP.

4 0
3 years ago
How to turn off microsoft teams message notifications
Andru [333]

Answer:

simply go to settings and turn it off.

Explanation:

i can help you

first tell you use pc or mobilephone

and secondly what type of notifications? message or call or meeting

5 0
3 years ago
What number is needed to complete the pattern 66, 73, 13, 21, 52,_, 10, 20?
Lilit [14]
66,73 73-66=7
13,21 21-13=8
10,20 20-10=10

the missing no. is 9 so
52+9=61.

the pattern is
66,73,13,21,52,61,10,20





8 0
3 years ago
Visual images taken directly from a source, such as pictures, charts, and graphs do not need a citation. true or false.
Pepsi [2]
False. they need citation
3 0
4 years ago
Let A and B be two stations attempting to transmit on an Ethernet. Each has a steady queue of frames ready to send; A’s frames w
Mariana [72]

Answer:

Following are the solution to the given question:

Explanation:

Please find the complete and correct question in the attachment file.  

For Point a:

For the second round,

A is selects kA(2)  either 0 or 1, so for each of them, that is \frac{1}{2}.

B selects kB(2)\  from\  (0, 1, 2, 3) for each choice with the probability of \frac{1}{4}.

If kA(2) < kB(2) wins the second rear race.

\to P[A \ wins] = P[kA(2) < kB(2)]

                     = P[kA(2) = 0] \times P[kB(2) > 0] + P[kA(2) = 1] \times P[kB(2) > 1]\\\\= \frac{1}{2} \times \frac{3}{4}  + \frac{1}{2}  \times \frac{2}{4} \\\\=\frac{3}{8}  +\frac{2}{8} \\\\= \frac{3+2}{8}\\\\= \frac{5}{8}

For Point b:

Throughout this example, kA(3) also selects to be either 0 or 1 with such a \frac{1}{2} probability. So, although B chooses kB(3) from (0, 1, 2, 3, 4, 5, 6, 7), the probabilities each are \frac{1}{8}:

\to P[A \  wins] = P[kA(3) < kB(3)]

                     = P[kA(3) = 0] \times P[kB(3) > 0] + P[kA(3) = 1] \times P[kB(3) > 1]\\\\= \frac{1}{2} \times \frac{7}{8} + \frac{1}{2} \times \frac{6}{8}\\\\= \frac{7}{16} + \frac{6}{16}\\\\= \frac{7+6}{16} \\\\= \frac{13}{16}\\\\

For point c:

Assume that B tries again 16 times (typical value), and it destroys. In addition, throughout the exponential background n is obtained at 10 when choosing k between 0 to 2n−1. The probability of A winning all 13 backoff events is: P[A \text{wins remaining races}] = 16\pi i =4P[A \ wins \ i |A \ wins \ i -1 ]

Let the k value kA(i) be A for the backoff race I select. Because A retains the breed

=(kA(i)] \cdot P[kA(i+ 1)< kB(i+ 1)] \geq P[kA(i) + 1

For point d:

Two stations A and B are supposed. They assume that B will try 16 times afterward. Even so, for A, 16 races were likely to also be won at a rate of 0.82 For Just higher expectations of three A, B, and C stations. For Station A, possibility to win all backoffs

3 0
3 years ago
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