Answer: I think
GIVEN TRIANGLE PQR WITH P(1,6) Q(3,1) AND R(8,3). WHAT POINT BISECTS PQ? B) WHY DO SLOPES OF THE PQ AND QR SHOW THAT M
Step-by-step explanation:
Step-by-step explanation:
I think angle A = 21 degree
because in the question there is angle A Is twice means angle a + angle a= 4G degree
2 angle a=42 degree
42 divides by 2
answer is 21 degree
At point of intersection the two equations are equal,
hence, 6x³ =6x²
6x³-6x²=0
6x²(x-1)=0 , the values of x are 0 and 1
The points of intersection are therefore, (0,0) and (1,6)
To find the slopes of the tangents at the points of intersection we find dy/dx
for curve 1, dy/dx=12x, and the other curve dy/dx=18x²
At x=0, dy/dx=12x =0, dy/dx=18x² = 0, hence the angle between the tangents is 0, because the tangents to the two curves have the same slope which is 0 and pass the same point (0,0) origin.
At x=1, dy/dx =12x = 12, dy/dx= 18x² =18, Hence the angle between the two tangents will be given by arctan 18 -arctan 12
= 86.8202 - 85.2364 ≈ 1.5838, because the slope of the lines is equal to tan α where α is the angle of inclination of the line.