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3 years ago

What is the correct reason for 1+3x+4x

Mathematics

1 answer:

8_murik_8 [283]3 years ago

6 0

Add all common numbers & variables together.

1 + 3x + 4x

1 + 7x

hope this helps

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Ashley and Kris are saving money for a vacation. Ashley currently has

USPshnik [31]

Answer:

Step-by-step explanation:

1) y = 50x + 2500

2) y = 200x + 1000

if we build a system with the two equations, we have:

50x+2500 = 200x + 1000

150x = 1500

x = 10

y = 2000 + 1000 = 3000

3) 10

4) $3000

8 0

3 years ago

What is 6 to the power of 2 divided by 2 times 3 plus 4

lidiya [134]

$6^{2}$ ÷ $2*3+4$

You use the order of operations with PEMDAS

P⇒Parentheses

E⇒Exponents

M⇒Multiplication

D⇒Division

A⇒Addition

S⇒Subtraction

$6^{2}$ ⇒ $6*6=36$

$36*3=108$

$108$ ÷ $2=54$

$54+4=58$

Answer: 58

8 0

4 years ago

Read 2 more answers

What's the equation of the line that passes through the points (4,4) and (0,-12)?

Law Incorporation [45]

Answer:

Step-by-step explanation:

You need to find the slope.

$m=\frac{y_{2}-y_{1} }{x_{2}- x_{1} }\\m=\frac{-12-4 }{0-4 }\\m=\frac{-16}{-4}\\ m=4$

Since the slope is 4, the answer is B.

6 0

3 years ago

in the year 2005 a company made $6.6 million in profit for each consecutive year after that their profit increase by 9% how much

posledela

Answer:

$9.3 million

Step-by-step explanation:

Given that the company profit increases by 9% yearly from 2005.

Using the exponential growth formula;

A = P(1+r)^(t) .....1

Where;

A = final amount/value of profit

P = initial amount/value = $6.6 million

r = growth rate yearly = 9% = 0.09

t = time of growth in years = 2009 - 2005 = 4 years

Substituting the values;

A = 6.6(1+0.09)^(4)

A = 6.6(1.09)^(4)

A = 9.3164386 million

A = $9.3 million

The companies profit in the year 2009 to the nearest 10th of $1 million is $9.3 million

5 0

3 years ago

Find the area of the quadrilateral using the sine and cosine rules

diamong [38]

It would be easier to explain if the vertices were labeled.

Let's call the horizontal diagonal of the kite c.

The area of the triangle with sides $5/6/c$ triangle is given by

$A_1 = \frac 1 2 ab\sin C = \frac 1 2 (5)(6)\sin 65$

c itself is given by the Law of Cosines:

$c^2 = 5^2 + 6^2 - 2(5)(6)\cos 65^\circ = 35.6429$

At this point I'd use a variation on Heron's formula to calculate the area. But the question says to use the sine and cosine rules so we'll do it that way.

The opposite angle, call it D, is given by the law of Cosines. We need its sine so we don't actually have to calculate the angle:

$c^2 = 4^2 + 2.5^2 - 2(4)(2.5) \cos D$