Please help!!!!!!!!!!!!

Mathematics

1 answer:

Svetllana [295]2 years ago

8 0

A,B,F.....................

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You are asked to draw a triangle using three of the following angles: 0°, 30°, 45°, 55°, 60°, 80°, 90°, 105°. Which triangle can

BabaBlast [244]

Any triangle where the sum of the angles is over or under 180 cannot exist.
A 45-55-80 triangle can exist, but a 45-55-90 triangle cannot.
A 30-45-105 triangle can exist, but a 80-90-105 triangle cannot.

6 0

2 years ago

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Round 11 580 to 3 significant figures

Dmitriy789 [7]

11,580 to 3 significant figures
Currently, the value has 5 significant figures ( inclusive of 0 )
next to 5, there is 8 and 8 > 5, so 5 rounds up
1.16 x 10⁴

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2 years ago

11) A marketing research company is estimating the average total compensation of CEOs in the service industry. Data were randoml

Illusion [34]

Answer:

The confidence interval would be more narrow if the confidence level were changed to 90%

Step-by-step explanation:

For a small sample size of n = 18 a pivotal quantity that we can use to form a confidence interval for $\mu$ is given by $T=\frac{\bar{X}-\mu}{S/\sqrt{n}}$ that has a t distribution with (n-1) degrees of freedom. We find a $100(1-\alpha)$ % confidence inverval using $P(-t_{\alpha/2}\leq T \leq t_{\alpha/2}) = 1-\alpha$ , where $t_{\alpha/2}$ is the t-value such that there is an area equal to $\alpha/2$ above this t-value and below the curve of the density of the t distribution with n-1 df. We find a 95% confidence interval with $P(-t_{0.025}\leq T\leq t_{0.025}) = 0.95$ and we find a 90% confidence interval with $P(-t_{0.05}\leq T\leq t_{0.05}) = 0.90$ . Because of $-t_{0.025} < -t_{0.05}$ and $t_{0.05} < t_{0.025}$ , the confidence interval would be more narrow if the confidence level were changed to 90%.