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tatuchka [14]
3 years ago
9

Given that a function receives three parameters a, b, c, of type double, write some code, to be included as part of the function

, that determines whether the value of "b squared" – 4ac is negative. If negative, the code prints out the message "no real solutions" and returns from the function.
Computers and Technology
1 answer:
Ray Of Light [21]3 years ago
4 0

Answer:

The function, having three double parameters, for the given scenario in c++ is given below.

void calc(double a, double b, double c)

{

   double res, s;

   s = b*b;

   res = s - (4*a*c);

   if(res < 0)

       cout << "no real solutions" << endl;

}

Explanation:

A function is declared as follows.

return-type function-name (parameter1, parameter2, … )

1. The return-type can be void or any other data type in c++ language. Void indicates that the function does not returns anything. Other data types indicate that the function returns a value of that particular data type.

2. Here, the return type is taken as void since question does not asks to return any value from the function.

3. The function-name is the name of the function. The naming conventions are similar to those defined for variables in c++.

4. The brackets following the function-name consists of the parameters. The parameters are optional and the bracket can be empty.

5. The parameters are declared in the same way as the normal variables.

The function executes as explained.

1. The function calc() receives three double parameters a, b and c.

2. No user input is taken inside the function.

3. Two additional variables are declared which are used as given below. These variables are also declared as double.

4. Square of value in variable b is stored in the variable, s.

5. The final value of the expression, s - 4ac (equivalent to b squared – 4ac), is stored in the variable, res.

6. If the value of variable res is less than 0 or negative, the function displays a message, “no real solutions” to the standard output.

7. If the value of variable res is more than or equal to 0, the function does not display any message to the standard output.

8. As per the question, message should be displayed only for the negative value of the expression.

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Answer:

import java.util.Scanner;

import java.util.Arrays;

import java.util.Random;

public class Main {

 public static void main(String[] args) {

   Scanner scan = new Scanner(System.in);

   System.out.print("Enter low: ");

   int low = scan.nextInt();

   System.out.print("Enter high: ");

   int high  = scan.nextInt();

   scan.close();

   int rndnumbers[] = new int[10];

   Random r = new Random();

   for(int i=0; i<rndnumbers.length; i++) {

     rndnumbers[i] = r.nextInt(high-low+1) + low;

   }

   for(int i=0; i<rndnumbers.length; i++) {

     System.out.printf("%d: %d\n", i, rndnumbers[i]);

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4 0
3 years ago
What is imagined risk
lara31 [8.8K]
Hello there!

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Hope This Helps You!
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3 0
4 years ago
Assume the method doSomething has been defined as follows: public static void doSomething (int[] values, int p1, int p2) { int t
Dmitriy789 [7]

Answer:

The answer to this question is option "b".

Explanation:

In the method definition, we perform swapping. To perform swapping we define a variable "temp" that swap values of variable p1 and p2 and store in array that is "values". and other options are not correct that can be defined as:

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3 years ago
100 Base-T: Group of answer choices
Allisa [31]

Answer:

can run at either full- or half-duplex

Explanation:

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It uses Shielded Twisted Pair (STP) cabling system.

The Variations of 100BaseT are;

- 100BaseTX

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8 0
3 years ago
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

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So, we can just estimate binomial distribution to normal distribution

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Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

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So, likelihood that fewer than 120 have a PC

= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

6 0
3 years ago
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