This is how I'd set it up:
405/20 = 243/x
this means the mpg (miles / gallons) for 1 situation is the same as the mpg for the other situation (because the rate is the same)
then just cross multiply and solve:
405x=243*20 or 405x=4860 or x = 12
he would need 12 gallons of gas for 243 miles
1. 0.95 x 6700 = 6365
2. 0.45 x 910 = 409.5
Recall that all three angles in a triangle equals 180.
Knowing this, we just have to add up all the angles and figure out what the value 'x' is.
(x-22 + x-17 + 3x+19) = 180
Simplify:
5x - 20 = 180
Add 20 to both sides:
5x = 200
Divide both sides by 5:
x = 40
Now that we found the value for x, we need to solve for angle A.
Simply input the value of 'x' into angle A's equation:
40 - 22 = 18
Angle A = 18 degrees
Good luck! If you need me to explain anything, just ask :))
-T.B.
Median: middle number
Mean: average
How to calculate the median:
1) line the numbers in order from least to greatest
0 1 2 4 5 24
(you do not need to write all the fours or fives, one four or five is enough to represent it)
2) Next, take one number off each end at a time until you have one number in the middle left (if there are two numbers left in the middle, add them together, than divide them by two)
3) The median is 4 becuase it is in the middle.
How to calculate the mean:
1) Add all the numbers together
0+24+1+4+5+2+5+4 = 45
2) Now we divide 45 by 8 because there are eight numbers in the list
45/8 = 5
3) The mean is 5.
Answer: Median = 4, Mean = 5
live with love, live with Jesus
Answer:
A sample of 18 is required.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Z-table as such z has a p-value of 
.
That is z with a pvalue of 
, so Z = 1.88.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
A previous study indicated that the standard deviation was 2.2 days.
This means that 
How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?
This is n for which M = 1. So
Rounding up:
A sample of 18 is required.
