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3 years ago

Find the root of the polynomial by guessing possible candidates of the root.

Mathematics

1 answer:

Andrew [12]3 years ago

6 0

A- x=1
b-x=1 and -1
c-x= 3
d=-10

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Find the hcf of 299, 589 and 779

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Just search up GCF calculator

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3 years ago

HELP ME ASAP <br> Also please tell me how to do this

ss7ja [257]

Answer:go to a physiatrist r-tard

Step-by-step explanation:

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3 years ago

I need help this question?

Masja [62]

Answer:

Correct answer: F. graph F or x ∈ |-5 ; 5| (including endpoints)

Step-by-step explanation:

Let us first define the absolute value:

| x | = 1. { x with condition x ≥ 0 }

or 2. { - x with condition x < 0 }

This is a linear inequality

1. x ≤ 5 ∧ x ≥ 0 ⇒ 0 ≤ x ≤ 5 or interval x ∈ |0 ; 5| (including endpoints)

2. - x ≤ 5 when we multiply both sides of the equation by -1 we get:

x ≥ -5 ∧ x < 0 ⇒ -5 ≤ x < 0 or interval x ∈ |-5 ; 0) (including -5)

The solution to this linear inequality is the union of these two intervals:

x ∈ |-5 ; 0) ∪ |0 ; 5| ⇒ x ∈ |-5 ; 5| (including endpoints)

x ∈ |-5 ; 5| (including endpoints)

God is with you!!!

7 0

3 years ago

Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

$T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326$

What is the probability that they are both queens?

$P = \frac{D}{T} = \frac{6}{1326} = 0.0045$

0.45% probability that they are both queens.

4 0

3 years ago

the sum of two numbers is 100. The first number plus twice the second number is 200. what are the numbers

lutik1710 [3]

it can be any number between 0 and 100

5 0

3 years ago

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