Question

At each scooter's top speed brand a goes 2 miles per hour faster than brand b. After traveling at its top speed for 3 hours brand a scooter traveling 40.2

Answer 1

Question is Incomplete, Complete question is given below.

Brand A scooter has a top speed that goes 2 miles per hour faster than Brand B. If after 3 hours, Brand A scooter traveled 40.2 miles at its top speed, at what rate did Brand B scooter travel at its top speed if traveled the same distance? Write an equation to determine the solution.

Answer:

The equation to determine solution is  $40.2 = (2+x)3$.

Brand B will travel at a rate of 11.4 miles per hour.

Step-by-step explanation:

Given:

Distance traveled by brand A = 40.2 miles

time required to cover distance = 3 hours.

Brand A scooter has a top speed that goes 2 miles per hour faster than Brand B

Let brand B scooter has a top speed of x

Hence Brand A scooter has a top speed will be $2 + x$

Now we know that Distance traveled by brand A scooter is equal to Brand A scooter top speed multiplied by time reuired to cover the distance by brand A $40.2 = (2+x)3$.

Hence the equation to determine solution is  $40.2 = (2+x)3$

Now we will find the rate of brand B by solving the same we get.

$40.2 = 6+3x\\3x = 40.2-6\\3x = 34.2\\x= 11.4 \ m/h$

Hence Brand B will travel at a rate of 11.4 miles per hour.