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rosijanka [135]
4 years ago
12

Santiago has a rope that measures 205.95 centimeters. Write the number in a expanded form

Mathematics
2 answers:
Ivanshal [37]4 years ago
6 0

Expanded Notation Form:

 200  

+ 0  

+ 5  

+   0.9

+   0.05

Expanded Factors Form:

 2 × 100  

+ 0 × 10  

+ 5 × 1  

+ 9 ×   0.1

+ 5 ×   0.01

Expanded Exponential Form:

2 × 102

+ 0 × 101

+ 5 × 100

+ 9 × 10-1

+ 5 × 10-2

Word Form:

two hundred five and ninety-five hundredths


Sergio [31]4 years ago
3 0

Answer:

Therefore,  200 + 5 + \frac{9}{10}+  \frac{5}{100}.

Step-by-step explanation:

Given  : 205.95 centimeters.

To find : Write the number in a expanded form.

Solution : we have given 205.95 centimeters.

We can see 2 is at hundred place = 200.

0 is at tens place = 00.

5 is at ones place  = 5.

9 after decimal is at tenth place = \frac{9}{10}.

5 is at hundredth place  =  \frac{5}{100}.

Then ,

Expanded form : 200 + 5 + \frac{9}{10}+  \frac{5}{100}.

Therefore,  200 + 5 + \frac{9}{10}+  \frac{5}{100}.

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distributive property

3 0
3 years ago
What is the standard form given the vertex (-3,3) and the focus point (-3,2)
baherus [9]

Answer:

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{3}{4}

Step-by-step explanation:

The standard form of a parabola is written as

y=ax^2+bx+c

where a, b and c are the coefficients of the second-degree, first degree and zero-degree terms.

The coordinates of the vertex of a parabola is given by:

x_b = -\frac{b}{2a}

y_b=c-\frac{b^2}{4a}

The coordinates of the focus instead are given by

x_f=-\frac{b}{2a}

y_f=y_b+\frac{1}{4a}

In this problem, we know the coordinates of the vertex and of the focus point:

Vertex: (-3,3)

Focus point: (-3,2)

So we have:

x_b=-3=-\frac{b}{2a} (1)

y_b=3=c-\frac{b^2}{4a} (2)

y_f=2=y_b+\frac{1}{4a} (3)

From eq.(1) we get

2a=\frac{b}{3} (4)

Substituting into (2),

3=c-\frac{b^2}{2(b/3)}\\3=c-\frac{3}{2}b\\c=3+\frac{3}{2}b(5)

Now rewriting eq.(3) as

2=y_b+\frac{1}{4a}\\2=(c-\frac{3}{2}b)+\frac{1}{4a}

And substituting (4) and (5) into this, we can find b:

2=((3+\frac{3}{2}b)-\frac{3}{2}b)+\frac{1}{2(b/3)}\\2=3+\frac{3}{2b}\\-1=\frac{3}{2b}\\b=-\frac{3}{2}

Then we can find a and c:

2a=\frac{b}{3}\\a=\frac{b}{6}=\frac{-3/2}{6}=-\frac{1}{4}

And

c=3+\frac{3}{2}b=3+\frac{3}{2}(-\frac{3}{2})=3-\frac{9}{4}=\frac{3}{4}

So the parabola is

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{3}{4}

4 0
4 years ago
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Answer: point C and D

Step-by-step explanation:

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7 0
3 years ago
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andriy [413]

Answer:

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Step-by-step explanation:

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Box 2’s volume is modeled by a monomial times a binomial, so it will be a binomial.

4 0
3 years ago
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