Answer:
Sarah's Store
Step-by-step explanation:
<span>The urn contains 2 purple balls and 4 white balls. The player pay $4 for start the game and get $1.5 for every ball drawn until one purple ball is drawn. The maximal revenue would be $7.5 when 4 white balls and 1 purple balls are drawn.
If the purple ball is p and white ball is w, t</span>he possible sample space of drawings are {p, wp, wwp, wwwp, wwwwp}
<span>1. Write down the probability distribution for the player earning
The player earning </span>for each event depends on the number of balls drawn subtracted the ticket price.<span>
p= 2/6
The player earnings would be: 1*$1.5 -$4= - $2.5
wp= (4*2)/(6*5) = 4/15
</span>The player earnings would be: 2*1.5- $4= - $1
wwp= (4*3*2)/(6*5*4)= 1/5
The player earnings would be: 3*$1.5 -$4= $0.5
wwwp= (4*3*2*2)/(6*5*4*3*2)= 2/15
The player earnings would be: 4*$1.5 -$4= $2
wwwwp= (4*3*2*2*1)/(6*5*4*3*2*1) = 1/15
The player earnings would be: 5*$1.5 -$4= $3.5
2. Find its expected value
The expected value would be:
chance of event * earning
You need to combine the 5 possible outcomes from the number 1 to get the total expected value.
Total expected value= (1/3 * - 2.5)+ (4/15*-1) + (1/5*0.5) + (2/15 *2) + ( 1/15 *3.5)=
(-12.5 -4 + 1.5 + 4 + 3.5) /15= -$7.5
This game basically a rip off.
Answer:
all real numbers less than or equal to –3
Step-by-step explanation:
Look at the y-values that the graph shows. There are none greater than -3. Any value of -3 or less is possible.
Answer:
So both equations are true
Step-by-step explanation:
#4 was asking you to substitute x = 4 into both equations to see if it's the solution of the equations.
Substitute x = 4
Ritz equation
y = 30x + 20
y = 30(4) + 20
y = 120 + 20
y = 140
Smits equation:
y = 15x + 80
y = 15(4) + 80
y = 60 + 80
y = 140
Both companies charged same price $140 for 4 days
So both equations are true
Given:
The geometric sequence is:
To find:
The 9th term of the given geometric sequence.
Solution:
We have,
Here, the first term is:
The common ratio is:
The nth term of a geometric sequence is:
Where, a is the first term and r is the common ratio.
Substitute 
to find the 9th term.
Therefore, the 9th term of the given geometric sequence is 5103.
