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3 years ago

What is the surface area of the cone? 12cm 19cm

Geography

1 answer:

Rina8888 [55]3 years ago

6 0

Answer:

2 things...

Explanation:

1: this question is in the wrong category

2: you didn't state which is the radius and which is the height but ill give answers for either way

r = 12cm h = 19cm then A≈1299.57

r = 19cm h = 12cm then A≈2475.49

this problem is super ez so once you do it 3-5 times it'll be a breeze for you. heres a site that might help.

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Which of the following ocean-floor features is associated with trenches?

slavikrds [6]

The ocean-floor feature that is associated with trenches is a subduction zone. An oceanic trench is characterized by a narrow and very deep depression on the sea floor. This depression is caused by a subduction zone wherein two plate boundaries converge and one sinks at the bottom of the other plate, forming a thin and deep region between the two plates.

6 0

3 years ago

Read 2 more answers

Please answer this fast and here only

Vaselesa [24]

Answer:

1) a) $r_{R,I} = 1150\,m$ , b) $r_{R,II} = 3400\,m$ , c) $r_{R,III} = 2750\,m$ .

2) a) $r_{R,I} = 45,2\,km$ , b) $r_{R, II} = 28,15\,km$ , c) $r_{R,III} = 51,8\,km$ .

Explanation:

The scale factor is defined by the following expression:

$n = \frac{r_{S}}{r_{R}}$ (1)

Where:

$n$ - Scale factor.

$r_{S}$ - Scale distance, in centimetres.

$r_{R}$ - Real distance, in centimetres.

1) If we know that $n = \frac{1}{50000}$ , $r_{S,I} = 2,3\,cm$ , $r_{S,II} = 6,8\,cm$ and $r_{S,III} = 5,5\,cm$ , then the actual distances in metres are:

$r_{R,I} = \frac{r_{S,I}}{n}$

$r_{R,I} = \frac{2,3\,cm}{\frac{1}{50000} }$

$r_{R,I} = 115000\,cm$

$r_{R,I} = 1150\,m$

$r_{R,II} = \frac{r_{S,II}}{n}$

$r_{R,II} = \frac{6,8\,cm}{\frac{1}{50000} }$

$r_{R,II} = 340000\,cm$

$r_{R,II} = 3400\,m$

$r_{R, III} = \frac{r_{S, III}}{n}$

$r_{R,III} = \frac{5,5\,cm}{\frac{1}{50000} }$

$r_{R,III} = 275000\,cm$

$r_{R,III} = 2750\,m$

2) If we know that $n = \frac{1}{50000}$ , $r_{S, I} = 90,4\,cm$ , $r_{S, II} = 56,3\,cm$ and $r_{S,III} = 103,6\,cm$ , then the actual distance in kilometres is: