No, the product is not valid. The number of columns of 
(five) should match the number of rows of 
(four).
Find the y and x-intercept for -x+3y+3
2 answers:
-x+3y+3=0 <-- This puts the expression into an equation to make it solvable.
3y+3=x <-- Use Addition Property of Exponents to move the (x) to the right
3y=x-3 <-- Use Subtraction Property of Exponents to move the (3) to the right
y=
-1 <-- Use Division Property of Exponents to remove the 3 from y
y=-1 < This is the equation for the y-intercept
-x+3y+3=0 <-- Same as above, makes it so the expression is an equation to solve
-x+3=-3y <-- Use Subtraction Property of Exponents to move the 3y to the right
-x=-3y-3 <-- Use Subtraction Property of Exponents to move the 3 to the right
x=3y+3 <--Use Divison Property of Exponents to remove the -1 from x
x=3y+3 <-- This is the equation for the x-intercept
Hope this helped!
3y+3=x <-- Use Addition Property of Exponents to move the (x) to the right
3y=x-3 <-- Use Subtraction Property of Exponents to move the (3) to the right
y=
y=
-x+3y+3=0 <-- Same as above, makes it so the expression is an equation to solve
-x+3=-3y <-- Use Subtraction Property of Exponents to move the 3y to the right
-x=-3y-3 <-- Use Subtraction Property of Exponents to move the 3 to the right
x=3y+3 <--Use Divison Property of Exponents to remove the -1 from x
x=3y+3 <-- This is the equation for the x-intercept
Hope this helped!
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Answer:
1. Mean square B= 5.32
2. Mean square E= 16.067
3. F= 0.33
4. p-value: 0.28
Step-by-step explanation:
Hello!
You have the information of 3 groups of people.
Group 1
n₁= 20
X[bar]₁= 3.2
S₁²= 14.3
Group 2
n₂= 20
X[bar]₂= 4.2
S₂²= 17.2
Group 3
n₃= 20
X[bar]₃= 7.6
S₃²= 16.7
1. To manually calculate the mean square between the groups you have to calculate the sum of square between conditions and divide it by the degrees of freedom.
Df B= k-1 = 3-1= 2
Sum Square B is:
∑ni(Ÿi - Ÿ..)²
Ÿi= sample mean of sample i ∀ i= 1,2,3
Ÿ..= general mean is the mean that results of all the groups together.
General mean:
Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (3.2+4.2+7.6)/3 = 5
Sum Square B (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (3.2 - 5)² + (4.2 - 5)² + (7.6 - 5)²= 10.64
Mean square B= Sum Square B/Df B= 10.64/2= 5.32
2. The mean square error (MSE) is the estimation of the variance error (σ →
), you have to use the following formula:
Se²=<u> (n₁-1)S₁² + -(n₂-1)S₂² + (n₃-1)S₃²</u>
n₁+n₂+n₃-k
Se²=<u> 19*14.3 + 19*17.2 + 19*16.7 </u>= <u> 915.8 </u> = 16.067
20+20+20-3 57
DfE= N-k = 60-3= 57
3. To calculate the value of the statistic you have to divide the MSB by MSE
4. P(F ≤ F) = P(F
≤ 0.33) = 0.28
I hope you have a SUPER day!
Let
x-------> the number of game tokens purchased for a member of the arcade
y-------> the function of the yearly cost in dollars
we know that
the function y of the yearly cost in dollars is equal to
This is the equation of the line
using a graph tool
see the attached figure
<u>Statements</u>
<u>case a)</u> The slope of the function is $1.00
The statement is False
The slope of the function is equal to
<u>case b)</u> The y-intercept of the function is $60
The statement is True
we know that
The y-intercept of the function is the value of the function when the value of x is equal to zero
so
for
<u>case c)</u> The function can be represented by the equation y =(1/10)x + 60
The statement is True
The equation of the function is equal to
<u>case d)</u> The domain is all real numbers
The statement is False
The value of x cannot be negative, therefore the domain is the interval
[0,∞)
<u>case e)</u> The range is {y| y ≥ 60}
The statement is True
The range of the function is the interval-------> [60,∞)
see the attached figure
