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3 years ago

Explain how these three models are related

Mathematics

1 answer:

Romashka [77]3 years ago

6 0

They are related, because they are both 100 blocks, and when you add them together it equals 300. So that's why I think they are related.

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4 years ago

Read 2 more answers

Do you think the equations (x−1)(x+3)=17+x and (x−1)(x+3)+500=517+x should have the same solution set? Why?

oksano4ka [1.4K]

Answer:

Those two pair of equations have the same solution set.

Step-by-step explanation:

There are two equations

(x-1)(x+3)=17+x ..... (1) and

(x-1)(x+3)+500=517+x ...... (2)

We have to check the same solution set will be there for equations (1) and (2) or not.

Now, we are going to rearrange the equation (2).

(x-1)(x+3)+500=517+x

⇒ (x-1)(x+3)=517-500+x

⇒(x-1)(x+3)=17+x

This is the same equation as equation (1).

Therefore, there will be the same solution set for equations (1) and (2). (Answer)

There are two equations

(x-1)(x+3)=17+x ..... (3) and

3(x-1)(x+3)+500=51+3x ...... (4)

We have to check the same solution set will be there for equations (3) and (4) or not.

Now, we are going to rearrange the equation (4).

3(x-1)(x+3)+500=51+3x

⇒ 3(x-1)(x+3)=3(17+x)

⇒(x-1)(x+3)=17+x

This is the same equation as equation (3).

Therefore, there will be the same solution set for equations (3) and (4). (Answer)

7 0

3 years ago

According to the document Current Population Survey, published by the U.S. Census Bureau, 30.4% of U.S. adults 25 years old or o

Marizza181 [45]

Answer:

0.0803 = 8.03% probability that the number who have a high school degree as their highest educational level is exactly 32.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school degree as their highest educational level, or they do not. The probability of an adult having it is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

30.4% of U.S. adults 25 years old or older have a high school degree as their highest educational level.

This means that $p = 0.304$

100 such adults

This means that $n = 100$

Determine the probability that the number who have a high school degree as their highest educational level is a. Exactly 32

This is P(X = 32).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 32) = C_{100,32}.(0.304)^{32}.(0.696)^{68} = 0.0803$

0.0803 = 8.03% probability that the number who have a high school degree as their highest educational level is exactly 32.

7 0

3 years ago

An article in Medicine and Science in Sports and Exercise "Maximal Leg-Strength Training Improves Cycling Economy in Previously

Hatshy [7]

Answer:

The 99% confidence interval for the mean peak power after training is [299.4, 330.6]

$299.4\leq\mu\leq 330.6$

Step-by-step explanation:

We have to construct a 99% confidence interval for the mean.

A sample of n=7 males is taken. We know the sample mean = 315 watts and the sample standard deviation = 16 watts.

For a 99% confidence interval, the value of z is z=2.58.

We can calculate the confidence interval as:

$M-z\sigma/\sqrt{n}\leq\mu\leq M+z\sigma/\sqrt{n}\\\\315-2.58*16/\sqrt{7}\leq\mu\leq 315+2.58*16/\sqrt{7}\\\\315-15.6\leq \mu\leq 315+15.6\\\\299.4\leq\mu\leq 330.6$

The 99% confidence interval for the mean peak power after training is [299.4, 330.6]

5 0

3 years ago