Answer:
Yes
Step-by-step explanation:
This is possible of the rectangle is a square and it has the extra properties where its sides are parallel to each other and one pair is longer than the other.
Answer:
See the attachment for a plot
Step-by-step explanation:
I find it convenient to plot lines using their x- and y-intercepts, when those are integers. To find the intercepts, we can divide the equation by the constant on the right:
x/10 +y/5 = 1
This is "intercept form". The denominator in each term is the corresponding intercept:
the x-intercept is 10, point (10, 0)
the y-intercept is 5, point (0, 5)
We can choose another value of y to find a third solution. Let y=2. Then we have ...
-x -2(2) = -10 . . . . . put 2 for y in the original equation
-x = -6 . . . . . . . . . . add 4
x = 6 . . . . . . . . . . . . multiply by -1
A third point is (6, 2)
B because when you calculate it it should be it
Following the rules of PEMDAS:
We would do exponents before the division
27 ^ 2 = 729
27 ^ 4 = 531,441
729/531441/3 = 0.000456247 approximately
Answer:
40
Step-by-step explanation:
let the numbers be a+b+c+d.
the average of 4 numbers is 38
; (a+b+c+d)/4 = 38
(a+b+c+d) = 152 ......equ1
the average of the first two numbers is 42
; (a+b)/2 = 42
(a+b) = 84 ...... equ2
the average of the last three numbers is 36
; (b+c+d)/3 = 36
(b+c+d) = 108 .....equ3
substitute equ3 into equ1
a + 108 = 152
a= 152 - 108
a = 44
input the value of a into equ2
44 + b = 84
b = 40
the second number is 40.
I hope this helps.