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ehidna [41]
4 years ago
8

What expression can be used to 80% of 120

Mathematics
2 answers:
12345 [234]4 years ago
8 0

Answer:

59%

Step-by-step explanation:

Cloud [144]4 years ago
6 0

Answer:

96=80% of 120

Step-by-step explanation:

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A magazine has 120 pages. There are 28 full-page ads and 12 half-page ads. The rest of the magazine consists of articles.
Finger [1]

Answer:

120 = 28 + 12(½) + X

Where X is the no. of pages of articles

120 = 28 + 6 + X

X = 120 - 34

X = 86

4 0
3 years ago
Read 2 more answers
Tramserran? Do you think you could lend a hand for these questions? You have saved my life on more than one occasion. It's Algeb
Makovka662 [10]

Answer:

#1). 6 , 18 , 54

#2). 5/3 , 14 / 9 , 41/27

#3). 1.5 , 2.5 , 2.5

Step-by-step explanation:

#1).

g(x) = 3x

g(2) = 3 . 2 = 6

g²(2) = 3 . 3 . 2 = 18

g³(2) = 3 . 3 . 3 . 2 = 54

#2).

g(x) = 1/3 x + 1

g(2) = 2/3 + 1 = 5/3

g²(2) = g(5/3) = 5/9 + 1 = 14/9

g³(2) = g(14/9) = 14/27 + 1 = 41/27

#3).

g(x) = -1 ║x - 2 ║ + 3

g(0.5) = -1 (1.5) + 3 = 1.5

g²(0.5) = g(1.5) = -1(0.5) + 3 = 2.5

g³(0.5) = g(2.5) = -1(0.5) + 3 = 2.5

8 0
3 years ago
Read 2 more answers
Can anyone please help me with this I have to get it done before tomorrow
lions [1.4K]
Titania is the greatest because it has the largest magnitude(exponent). than obreron than ariel than umbriel and finally miranda
4 0
4 years ago
Solve the equation 3^(2x) -4*3^(x+1) + 27 = 0. use rules of exponents to change 3^(x+1)​
Leviafan [203]

Answer:

\huge\boxed{x=1\ \vee\ x=2}

Step-by-step explanation:

3^{2x}-4\cdot3^{x+1}+27=0\\\\\text{use}\ (a^n)^m=a^{nm}\ \text{and}\ a^n\cdot a^m=a^{n+m}\\\\\left(3^x\right)^2-4\cdot3^x\cdot3^1+27=0\\\\\left(3^x\right)^2-12\cdot3^x+27=0\\\\\text{substitute}\ 3^x=t>0\\\\t^2-12t+27=0\\\\t^2-3t-9t+27=0\\\\t(t-3)-9(t-3)=0\\\\(t-3)(t-9)+0\iff t-3=0\ \vee\ t-9=0\\\\t-3=0\qquad\text{add 3 to both sides}\\\boxed{t=3}\\\\t-9=0\qquad\text{add 9 to both sides}\\\boxed{t=9}

\text{We return to substitution:}\\\\3^x=t\\\\3^x=3\ \vee\ 3^x=9\\\\3^x=3^1\ \vee\ 3^x=3^2\\\\\boxed{x=1}\ \vee\ \boxed{x=2}

4 0
3 years ago
The question I need help in is the middle one. PLEASE I NEED ANDWER ASAP!
antoniya [11.8K]

Answer:

3.25

Step-by-step explanation:

I plugged in 5 for x and got 3.25 when I solved

4 0
4 years ago
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