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3 years ago

If 15 is added to a number the result is 56 less than twice the number

1 answer:

3 0

Let, the number = x
It would be: x + 15 = 2x - 56
2x - x = 15 + 56
x = 71

In short, Your Answer would be 71

Hope this helps!

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What is the difference?

ivann1987 [24]

Answer:

$= \frac{-2(x-6)}{(x+4)(x-4)}$

Step-by-step explanation:

Given the expression;

$\frac{x}{x^2-16} -\frac{3}{x-4}$

According to difference of two square;

x² - 16 = x²-4² = (x+4)(x-4)

Substitute;

$\frac{x}{(x+4)(x-4)} - \frac{3}{x - 4}\\$

Find the LCM

$= \frac{x-3(x+4)}{(x+4)(x-4)} \\= \frac{x-3x-12}{(x+4)(x-4)}\\= \frac{-2x-12}{(x+4)(x-4)}\\= \frac{-2(x-6)}{(x+4)(x-4)}$

3 0

3 years ago

Using the horizontal line test, which of the following can be concluded about

Helen [10]

Step-by-step answer:

A vertical line test checks for single or multiple intersections with a given relations If there is a maximum of one intersection with the relation at ANY point in the domain of the relation, we can conclude that the relation is a function. If there are multiple intersections of a VERTICAL line with the function, it is not a function.

Here, we see that vertical line test on the relation shown does not produce more than one intersection at any point in the domain of the relation, hence we conclude that the graph shows a function.

An inverse of a function is a reflection of the function about the y=x line. The result is the same as the interchange of the x and y-axes.

Hence a horizontal line test on the inverse of a function gives the same results as a vertical line test of the function itself, and the conclusion is identical to the test given above in paragraph two.

3 0

3 years ago

Verify that each equation is an identity (1 - sin^(2)((x)/(2)))/(1+sin^(2)((x)/(2)))= (1+cosx)/(3-cosX)

Allisa [31]

Answer:

Given that we have;

$sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }$

By the application of the law of indices and algebraic process of adding a and subtracting a fraction from a whole number, we have;

$\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) } =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}$

Step-by-step explanation:

An identity is a valid or true equation for all variable values

The given equation is presented as follows;

$\dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}$

From trigonometric identities, we have;

$sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }$

$\therefore sin^2 \left (\dfrac{x}{2} \right ) = \dfrac{1 - cos (x)}{2}$

$1 - sin^2 \left (\dfrac{x}{2} \right ) = 1 - \dfrac{1 - cos (x)}{2} = \dfrac{2 - (1 - cos (x))}{2} = \dfrac{1 + cos (x))}{2}$

$1 + sin^2 \left (\dfrac{x}{2} \right ) = 1 + \dfrac{1 - cos (x)}{2} = \dfrac{2 + 1 - cos (x))}{2} = \dfrac{3 - cos (x))}{2}$

$\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}$

3 0

3 years ago

What is 8x68 *******==

madreJ [45]

8 times 68 is 544 i hope i helped

6 0

3 years ago

Read 2 more answers

What is the circumference of a circle with a diameter of 57 centimeters

ss7ja [257]

C = 2πr or C = πd

Diameter d = 57 cm

C = πd

C = π*57 = 57π

C ≈ 57 * 3.14159 = 179.07063

Exact circumference is 57π cm or

≈ 179.07 cm.

6 0

3 years ago