I believe it gives you the answer. It should be one fifth or 20%. #TeamAlvaxic
The process of RNA editing is the alteration of the sequence of nucleotides in the RNA after it has been transcribed from DNA, but before it is translated into a protein. RNA editing occurs by two distinct mechanisms:<em><u /><u>Substitution</u> <u>editing </u></em>and <u><em>Insertion/</em></u><em></em><u><em>deletion</em></u><em> <u>editing</u></em>.
<u><em>Substitution editing</em></u> is the chemical alteration of individual nucleotides. These alterations are catalyzed by enzymes that recognize a specific target sequence of nucleotides:
*Cytidine Deaminases that convert a C in the RNA to uracil.
*<em />adenosine deaminases that convert an A to inosine,which the ribosome translates as a G.<span>Thus a CAG codon</span><span> (for Gln) can be converted to a CGG codon (for Arg).
<em><u>*Insertion/deletion editing</u></em><em><u /></em><u /> is the insertion or deletion of nucleotides in an RNA.
These alterations are mediated by guide RNA molecules that base-pair as best they can with the RNA to be edited and serve as a template for the addition( or removal) in the target.</span>
Animals use the respiratory system to breathe in oxygen and other gases and expel gases like CO2, right? O2 in, CO2 out.
In this case, the black body colour is the dominant one. The white dog is homozygous recessive.
As the cross between the black female 2 and the white male results in all black pups. This means that the all the offsprings are heterozygotes and the Female 1 is homozygous recessive having a BB phenotype (where B codes for dominant allele).
As the cross between the black female and the white male results in four white and three black pups. This means that the all the black offsprings are heterozygotes, and the white ones are homozygous recessive and the Female 2 have a dominant and 1 recessive gene, and is a hetrozygotezygous recessive having a Bb phenotype (where B codes for dominant allele and b codes for recessive allele).
