Rodney is given two linear equations: x – y = 11 and 2x + y = 19. What value of x should he get as a solution for this system of
2 answers:
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Answer:
224 stamps.
Step-by-step explanation:
We have been given that Becki put 14 stamps on each page.
To find the total number of stamps that Becki put in the book we will multiply the number of stamps put on each page by the number of completely filled pages.
Therefore, Becki put 224 stamps in the book.
Let's consider the functions one by one.
i)
,
x --> -infinity means that x is a very very small negative number. To model it in our mind let's think of
. This number to an even power becomes 
... etc.
Indeed, we can see that the smaller the x, the greater the value
. In fact, as x --> -infinity, f(x)-->+infinity.
ii)
y=x,
this clearly means that the behaviors of x and y are identical.
As x --> -infinity, y --> -infinity as well.
iii) y=|x|,
We can think of x --> -infinity, again, as a very very small number, like. For this value of x, y is 
, that is 
.
Indeed, the smaller the x, the greater the y. As in the function in part (i), as x --> -infinity, f(x)-->+infinity.
iv)
y=1/x
consider the values of y for the following values of x:
for x=-10, -100, -1000, y is respectively -0.1, -0.01, -0.001.
We can see that the smaller the x, the closer y gets to 0.
Thus, <span>f(x)-->0 as x --> -infinity
</span>
v) n'th root of x in not defined for negative x, when n is even.
vi) y=b^x, b>0
Here note that b cannot be equal to 1, otherwise the function is not exponential.
Let b=5, consider the values of y for the following values of x:
for x=-10, -100, -1000, y is respectively
.
That is, the smaller the value of x, the closer y gets to 0.
Thus, <span>f(x)-->0 as x --> -infinity</span>
i)
x --> -infinity means that x is a very very small negative number. To model it in our mind let's think of
Indeed, we can see that the smaller the x, the greater the value
ii)
y=x,
this clearly means that the behaviors of x and y are identical.
As x --> -infinity, y --> -infinity as well.
iii) y=|x|,
We can think of x --> -infinity, again, as a very very small number, like
Indeed, the smaller the x, the greater the y. As in the function in part (i), as x --> -infinity, f(x)-->+infinity.
iv)
y=1/x
consider the values of y for the following values of x:
for x=-10, -100, -1000, y is respectively -0.1, -0.01, -0.001.
We can see that the smaller the x, the closer y gets to 0.
Thus, <span>f(x)-->0 as x --> -infinity
</span>
v) n'th root of x in not defined for negative x, when n is even.
vi) y=b^x, b>0
Here note that b cannot be equal to 1, otherwise the function is not exponential.
Let b=5, consider the values of y for the following values of x:
for x=-10, -100, -1000, y is respectively
That is, the smaller the value of x, the closer y gets to 0.
Thus, <span>f(x)-->0 as x --> -infinity</span>
