I believe the answer is all of the above
Answer:
By the time Mike left his house at 12:00 noon, Erik had already traveled: 2 x 70 mph =140 miles.
308 - 140 = 168 miles left.
Let the time when they meet =T
70T + 50T =168 miles, solve for T
T =7 / 5 =1.4 hours, or 1 hour and 24 minutes after 12:00 noon.
12 + 1.4 =1 O'clock + 24 minutes, or 24 minutes after 1:00 pm when they will meet.
We have
x = t³ ===> dx/dt = 3t²
y = t⁴ ===> dy/dt = 4t³
Then with the given parameteriztion, the line integral along C of x/y is








