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sergeinik [125]
3 years ago
11

the area of a parallelogram is 96 cm squared. The height of the parallelogram is 4 cm less than the length of the base. What is

the length of the base?
Mathematics
2 answers:
iVinArrow [24]3 years ago
7 0
Area = 96 cm^2
h=L - 4
b =L

Area = L * (L - 4)
96 = L^2 - 4L
0 = L^2 - 4L - 96
Now you just need to guess The answers have to differ by 4 and add to 96. They are relatively close together. The larger one is minus.
0 = (L - 12)(L+8)
The answer is the base = 12
The height = 8
L+8 gives nothing. Lengths don't have - results.
ohaa [14]3 years ago
6 0
24???????????????????????????????????????????????????????????????????????
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Is {(5, 12), (-4,9), (-2,-7), (-4,0), (3, 2)}<br> A function? Please help me
Anna71 [15]

Answer:

Not a function

Step-by-step explanation:

(-4,9), (-4,0)   : one input (-4) with 2 output -9 , 0

6 0
3 years ago
Can anyone give me a hint or answer this?
RideAnS [48]

Answer:

x=8.5

Step-by-step explanation:

∠AOC=68

∠COD= (2x+5)

∠AOC and ∠COD are complimentary angles. This means that when you add them together you get 90.

∠AOC + ∠COD = 90

68 + (2x+5) =90

2x+5=22

2x=17

x=8.5

8 0
3 years ago
A number minus 6 is few then 8
Alexandra [31]
7 I think is you answer
7 0
3 years ago
Read 2 more answers
Please help please these are short answers
atroni [7]

Answer: The answers are given below.


Step-by-step explanation:  The calculations are as follows:

(19) Weight of the puppy last week is

W_\ell=2\dfrac{1}{2}~\textup{lb},

and weight of the puppy this week is

W_p=7\dfrac{1}{4}=\dfrac{29}{4}~\textup{lb}.

Therefore, the weight gained by the puppy is given by

W_g=W_p-W_\ell=\dfrac{29}{4}-\dfrac{5}{2}=\dfrac{29-10}{4}=\dfrac{19}{4}=4\dfrac{3}{4}~\textup{lb}.

(20) Time taken in Route 1 = 1 hour 30 minutes.

Time taken in Route 2 = 1 hour 45 minutes.

Time taken in Route 3 = 1 hour 35 minutes.

Time taken in Route 4 = 1 hour 25 minutes.

Since we want to spent the least amount of time on the bus, so we will be taking route 4.

(21) Time taken by Nazia to complete her language arts homework is

H_\ell=\dfrac{4}{9}~\textup{hr},

and the time taken by Nazia to complete her Mathematics homework is

H_m=\dfrac{2}{9}~\textup{hr}.

Therefore, Nazia takes more time to complete Language Arts homework, by

H=H_\ell-H_m=\dfrac{4}{9}-\dfrac{2}{9}=\dfrac{2}{9}~\textup{hr}.

(22) Quantity of Aluminium collected by Maya is

A_m=\dfrac{4}{20}=0.2~\textup{lb},

and the quantity of Aluminium collected by her friend Abigail is

A_a=\dfrac{7}{8}=0.87~\textup{lb}.

Therefore,

(a) Abigail collected more aluminium

and

(b) Total Aluminium collected by both the girls is

T=A_m+A_a=\dfrac{4}{20}+\dfrac{7}{8}=\dfrac{8+35}{40}=\dfrac{43}{40}~\textup{lb}.

(23) Quantity of snow fall last Wednesday is

S_w=3\dfrac{1}{4}=3.25~\textup{in.},

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S_s=3\dfrac{4}{5}=3.8~\textup{in.}.

Therefore, quantity of snowfall was more on Sunday by

S=S_s-S_w=3\dfrac{4}{5}-3\dfrac{1}{4}=\dfrac{19}{5}-\dfrac{13}{4}=\dfrac{76-65}{20}=\dfrac{11}{20}~\textup{in.}.

Thus, all the questions are answered.

3 0
3 years ago
Emily is dividing 15 pounds of jelly beans into 3/4 lb. bags. How many individual bags will she need for all of the jelly beans?
klio [65]
X= # of individual bags

x= 15 lbs ÷ 3/4 lbs
15 is the same as 15 over 1
x= 15/1 ÷ 3/4
multiply by reciprocal of 3/4
x= 15/1 * 4/3
x= (15*4)/(1*3)
x= 60/3
x= 20

ANSWER: She will need D) 20 bags

Hope this helps! :)
3 0
3 years ago
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