1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksandrvk [35]
4 years ago
8

Aisha, Benoit, and Carleen are each thinking of a positive integer.

Mathematics
2 answers:
Margaret [11]4 years ago
5 0

Answer:

No, It is not necessarily true that the greatest common divisor of all three numbers is greater than 1.

Step-by-step explanation:

Consider the provided information.

It is given that Aisha's number and Benoit's number have a common divisor greater than 1.

Let us assume any number having common divisor greater than 1

Let say Aisha's number is 10 and Benoit's number is 14.

Now the common divisor in both the numbers are:

Aisha: 10 = 2×5

Benoit: 14 = 2×7

Here, the common divisor is 2.

Now, it is given that Aisha's number and Carleen's number also have a common divisor greater than 1.

Let us assume Carleen's number is 35. Thus the common divisor in both the numbers are:

Aisha: 10 = 2×5

Carleen: 35 = 5×7

Here, the common divisor is 5.

Benoit's number and Carleen's number also have a common divisor greater than 1.

Benoit: 14 = 2×7

Carleen: 35 = 5×7

Here, the common divisor is 7.

Now, we need to find that the greatest common divisor of all three numbers is greater than 1.

Aisha: 10 = 2×5

Benoit: 14 = 2×7

Carleen: 35 = 5×7

There is no common divisor greater than 1.

Hence, it is not necessarily true that the greatest common divisor of all three numbers is greater than 1.

ziro4ka [17]4 years ago
3 0
Question:
If
GCD(A,B)>1
GCD(B,C)>1
GCD(C,A)>1
is it *always* true that GCD(A,B,C)>1 ?

Answer: no
Following is a counter example: A=6=2*3, B=14=2*7, C=21=3*7
There is no GCD greater than 1 that divides ALL of A, B and C.
I am sure you will be able to find other counter examples.

You might be interested in
An energy bar company manufactures peanut butter and chocolate bars.
Ivenika [448]

Answer:

sold 120 chocolate bars

sold 140 peanut butter bars

Step-by-step explanation:

x = peanut butter bars

y = chocolate bars

x + y = 260, total lbs

0.25x + 0.30y = 71, money

solve double variable equation

multiply -4 on both sides for 2nd equation

-x + -1.2y = -284

add both equations together

-0.2y = -24

y = 120

x = 260 - 120

x = 140

sold 120 chocolate bars

sold 140 peanut butter bars

3 0
3 years ago
Please save my life from fail grades
Harlamova29_29 [7]

1/x is smallest when x is the largest it can be, so it is 1/3

1/y is smallest when y is the largest it can be, so it is 1/5

The average of 1/3 is 1/5 can be found by adding them together and dividing by 2:

1/3 + 1/5 = 5/15 + 3/15 = 8/15

Divide it by 2:

4/15

The answer is C.

5 0
4 years ago
The hcf of 55 and 99 is expressible in the form of 55m - 99 then the value of m is​
GuDViN [60]

Answer:

2

Step-by-step explanation:

HCF(55,99)= 11

  • 55m-99=11
  • 55m=110
  • m=110/2
  • m=2
5 0
3 years ago
What two prime numbers equal 85 when added together?
k0ka [10]

I started out trying to subtract a prime number from 85, and then
see whether I had a prime number remaining.  I did this several
times, before I slapped myself upside the head.

-- 85 is an odd number. 

-- To get an odd-number for a sum, you have to add one odd number
to one even number ... there's no other way.

-- So one of the prime numbers we're looking for must be
     an even number.

-- The ONLY even number that's a prime number is ' 2 '.
     So it must be one of them.

-- Subtract 2 from 85, and you have 83 left.
     Is 83 a prime number ?  Yes. 

-- So the two numbers are  2  and  83.

If 83 were not a prime number, this wouldn't work, and I would have said
"There is no such pair of numbers.".  That means it doesn't necessarily work
for every odd number.

Examples:

75  ===>  2 and 73 . \
55  ===>  2 and 53 .  \
45  ===>  2 and 43 .   \
                                     Both primes.  It works.

65  ===>  2 and 63 .  63 is not a prime. \
35  ===>  2 and 33 .  33 in not a prime.  \
                                                                   It doesn't work.

5 0
4 years ago
Given the vertices of M(1, 5) A(-1, 2), T(1, -1) H(3, 2), prove that MATH is a rhombus.​
Sidana [21]

Step-by-step explanation:

i have solved the question

7 0
3 years ago
Other questions:
  • A construction company purchased some equipment costing $300,000. The value of the equipment depreciates
    8·1 answer
  • The linear equation has 2(2 + 3) + 4x = 2(2x + 2) + 6
    11·2 answers
  • Catherine ran 1/2 of a mile yesterday.
    15·2 answers
  • 71/10 into a mixed number
    8·2 answers
  • solve this equation. Does the equation have one solution, no solution, or infinitely many solutions use the drop-down menus to e
    11·2 answers
  • WILL GIVE BRAINLYIST. HELP
    13·2 answers
  • The Holbrooks ordered 25 gallons of orange juice and 16 pints of cranberry juice for their resturant. How much juice do they hav
    12·1 answer
  • Need answer asap.......
    8·1 answer
  • How many lines of symmetry does this triangle have
    6·2 answers
  • System of equations 6x+5y=15<br> 3x+5y=12 (use subtustion)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!