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3 years ago

The coefficient of c/5 is

Mathematics

2 answers:

9966 [12]3 years ago

6 0

C/5 is the same as $\frac{1}{5}$ c. So, c is being multiplied by $\frac{1}{5}$ , and that is the coefficient.

dexar [7]3 years ago

4 0

The constant fraction 1/5 is the coefficient of the variable c in this problem.

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Nonsense will be reported!!

Ainat [17]

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2 years ago

What is the slope of all lines perpendicular to the line y=(2/3)x+7

Alexandra [31]

Answer:

The slope is -3/2

Step-by-step explanation:

A line that is perpendicular to another has the slope that has the sign reversed and is the reciprocal.

Example: Find the line perpendicular to y = 3x

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Next, you make the reciprocal which makes -3 into -1/3

Problem: Find the line perpendicular to y = (2/3)x + 7

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Next, you make the reciprocal which makes -2/3 into -3/2

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3 years ago

A box of cereal has 20 cups. If each serving of cereal is 1/2 of a cup, how many servings are in the box?

Tpy6a [65]

The cereal will have 40 servings

7 0

2 years ago

Read 2 more answers

Can you help me with my math questions

GrogVix [38]

$p^2+2(7)p+7^2=(p+7)^2$

Justification:

Given: $p^2+14p+49$

Split the middle term;

$=p^2+7p+7p+49$

Factor:

$=p(p+7)+7(p+7)$

$=(p+7)(p+7)$

$=(p+7)^2$

QUESTION 3a

The given expression for the area of the rectangle is $36x^2-12x+1$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$36x^2-12x+1=289$

$\Rightarrow (6x-1)^2=289$

$\Rightarrow (6x-1)(6x-1)=289$

$\Rightarrow l=(6x-1),w=(6x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow (6x-1)=\pm \sqrt{289}$

$\Rightarrow (6x-1)=\pm 17$

$\Rightarrow 6x=1\pm 17$

$\Rightarrow 6x=18 \:or\:6x=-16$

$\Rightarrow x=3 \:or\:x=-\frac{2}{3}$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17$

QUESTION 3b

The given expression for the area of the rectangle is $25x^2-50x+25$ .

This is equal to the indicated area which is $1225\;in^2$

This implies that

$25x^2-50x+25=1225$

$25(x^2-2x+1)=1225$

$(5(x-1))^2=35^2$

$5(x-1)5(x-1)=49$

$\Rightarrow l=5(x-1),w=5(x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow 5(x-1)=\pm \sqrt{1225}$

$\Rightarrow 5(x-1)=\pm 35$

$\Rightarrow x=1\pm 7$

$\Rightarrow x=8 \:or\:x=-6$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=5(8-1)=35,w=5(8-1)=35$

QUESTION 3c

The given expression for the area of the rectangle is $49x^2-56x+16$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$49x^2-56x+16=289$

$(7x-4)^2=289$

$(7x-4)(7x-4)=289$

$\Rightarrow l=(7x-4),w=(7x-4)$

Applying the laws of indices gives;

$(7x-4)^2=17^2$

This implies that;

$7x-4=17$

$7x=21$

$x=3in.$

The side length of this rectangle is

$\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.$

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3 years ago

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mr_godi [17]

Given that we need to determine the radius of the circle.

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As, we can see that, the distance from the center of the circle to the point on the circle is 11 cm.

Since, we know that, the radius is the distance from the center of the circle to the point on the circle then, the radius of the given circle is 11 cm

Thus, radius of the circle is 11 cm.

3 0

3 years ago