3 years ago

Find the sum 49+50+51+52+...+141+142

Mathematics

1 answer:

gayaneshka [121]3 years ago

7 0

Answer:

8977

Step-by-step explanation:

Hello,

$49+50+51+52+...+141+142\\\\=(48+1)+(48+2)+(48+3)+(48+4)+...+(48+93)+(48+94)\\\\=48\times 94+(1+2+3+4+...+93+94)\\\\=48\times 94 + \dfrac{94\times 95}{2}\\\\=47(48\times 2+95)=47\times 191=8977$

thanks

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