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bija089 [108]
3 years ago
9

Can someone plz help me thank you

Mathematics
1 answer:
rodikova [14]3 years ago
6 0
7.

Direct variation is:

\sf y=kx

Where 'k' is the constant of variation. Let's plug in y = -6 and x = 10 into the formula:

\sf -6=k(10)

Divide 10 to both sides:

\sf k=-\dfrac{3}{5}

Plug this in for 'k' in our formula:

\sf y=-\dfrac{3}{5}x

This is our formula. To find out what 'y' is when 'x' = 5, plug in 5 for 'x':

\sf y=-\dfrac{3}{5}(5)

Multiply:

\boxed{\sf y=-3}

9.

Let's plug in y = 9 and x = 8 into our formula:

\sf 9=k(8)

Divide 8 to both sides:

\sf k=\dfrac{9}{8}

So our equation is:

\sf y=\dfrac{9}{8}x

Now let's plug in 18 for 'y' to find out what 'x' is when y = 18:

\sf 18=\dfrac{9}{8}x

Divide 9/8 to both sides or multiply by its reciprocal 8/9:

\sf x=18\cdot\dfrac{8}{9}\rightarrow \boxed{\sf 16}
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