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natta225 [31]
3 years ago
13

Mr. Herman's class is selling candy for a school fundraiser. The class has a goal of raising $500 by selling c, boxes of candy.

For every box they sell, they make $2.75. Write and solve an equation how many boxes of candy they need to sell.
Mathematics
1 answer:
xeze [42]3 years ago
4 0

Answer:

about 181

Step-by-step explanation: What I did to find this is divide 500 divided by 2.75 and get 181.818181

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yanalaym [24]

Answer:

Step-by-step explanation: In a total eclipse of the moon, the inner part of Earth's shadow, called the umbra, falls on the moon's face. At mid-eclipse, the entire moon is in shadow, which may appear blood red. ... In a penumbral lunar eclipse, only the more diffuse outer shadow of Earth – the penumbra – falls on the moon's face.

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3 years ago
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In the expression 3x2y + 4x – 5x2y, are the terms 3x2y and –5x2y like terms? Explain by providing support for your answer.
loris [4]

Answer:

yes

Step-by-step explanation:

These are like terms because they  have the same variables and powers. The coefficients do not need to match for it to be considered a like term.

6 0
3 years ago
Plz help me get the answer right I been stuck trying to find the answer to these
Verizon [17]

Answer:

<h2><em> -12y² + 72y</em></h2>

Step-by-step explanation:

Use the distributive property: <em>a(b + c) = ab + ac</em>

<em>-12y(y - 6) = (-12y)(y) + (-12y)(-6) = -12y² + 72y</em>

8 0
3 years ago
A simple random sample from a population with a normal distribution of 103 body temperatures has x overbarequals98.90degrees Upp
Shtirlitz [24]

Answer:

98.90-1.984\frac{0.62}{\sqrt{103}}=96.98    

98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82    

The 95% confidence interval would be given by (96.98;100.82)    

Step-by-step explanation:

Information given

\bar X=98.90 represent the sample mean

\mu population mean (variable of interest)

s=0.62 represent the sample standard deviation

n=103 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=103-1=102

Since the Confidence is 0.95 or 95%, the significance is \alpha=0.05 and \alpha/2 =0.025, and the critical value for this case would be t_{\alpha/2}=1.984

And replacing we got:

98.90-1.984\frac{0.62}{\sqrt{103}}=96.98    

98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82    

The 95% confidence interval would be given by (96.98;100.82)    

8 0
3 years ago
What is 3n-2/5=7/10 solve please
Tems11 [23]

Answer:  \bold{n=\dfrac{11}{6}}

<u>Step-by-step explanation:</u>

\dfrac{3n-2}{5}=\dfrac{7}{10}\\\\\\10(3n-2)=5(7)\qquad \longrightarrow \quad \text{(cross multiplied)}\\\\30n-20=35\qquad \longrightarrow \quad \text{(distributed)}\\\\30n=55\qquad \longrightarrow \quad \text{(added 20 to both sides)}\\\\n=\dfrac{55}{30}\qquad \longrightarrow \quad \text{(divided 30 from both sides)}\\\\n=\dfrac{11}{6}\quad \longrightarrow \quad \text{(simplified fraction)}\\\\\\\large\boxed{n=\dfrac{11}{6}}\\

8 0
3 years ago
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