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svetlana [45]
4 years ago
13

Is

1" title=" {8}^{5 = 16 \times \frac{5}{2} } " alt=" {8}^{5 = 16 \times \frac{5}{2} } " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
suter [353]4 years ago
3 0
8^{5} =16* \frac{5}{2}

8^{5} = 32768\\16* \frac{5}{2} = 40

FALSE

Hope this helped!
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Multiply 613 by the reciprocal of −716.
Bumek [7]

Answer:

-613/716.

Step-by-step explanation:

The reciprocal of a number is basically that number upside down. to find the reciprocal of a whole number, you can just turn the number into a fraction, and put one as the numerator, and the original number as the denominator. given this information we know that the reciprocal of -716 is -1/716, so now yoj can simply cross multiply 613 by -1/716, which gives you -613/716.

5 0
3 years ago
choose the equation below that represents the line passing through the point (2, −4) with a slope of one half. y = one halfx 5 y
AlexFokin [52]
Hello,

One half may be written 0.5=1/2=1*2^(-1).

y+4=(x-2)*1/2==>y=x/2-5

Answer C


3 0
3 years ago
Read 2 more answers
What is the least common multiple of 6 and 12? Enter your answer in the box.<br><br> no links please
NNADVOKAT [17]

Answer:

12

Step-by-step explanation:

2   | 6         ,        12

2   | 3          ,        6

3   | 3          ,         3    

    | 1           ,          1

LCM = 2 x 2 x 3 = 12

8 0
2 years ago
Determine whether the three points are the vertices of a right triangle. (6, -6), (9, -6), (9, 1)
lisabon 2012 [21]

Answer:

The three given points are the vertices of a right triangle.

Step-by-step explanation:

To determine that the three points are the vertices of a right triangle let us find the distance between each two points

The formula of the distance is d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }

∵ x_{1} = 6 and y_{1} = -6

∵ x_{2} = 9 and y_{2} = -6

∴ d_{1} = \sqrt{(9-6)^{2}+(-6--6)^{2}}=\sqrt{9+0}

∴ d_{1} = 3

∵ x_{1} = 6 and y_{1} = -6

∵ x_{2} = 9 and y_{2} = 1

∴ d_{2} = \sqrt{(9-6)^{2}+(1--6)^{2}}=\sqrt{9+49}

∴ d_{2} = \sqrt{58}

∵ x_{1} = 9 and y_{1} = 1

∵ x_{2} = 9 and y_{2} = -6

∴ d_{3} = \sqrt{(9-9)^{2}+(-6-1)^{2}}=\sqrt{0+49}

∴ d_{3} = 7

<em>Let us use the fact that if the square of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle at the vertex which opposite to the longest side</em>

∵ The longest side is \sqrt{58}

∵ The other two sides are 3 and 7

∵ ( \sqrt{58} )² = 58

∵ (3)² + (7)² = 9 + 49 = 58

∴  ( \sqrt{58} )² = (3)² + (7)²

- By using the fact above

∴ The triangle is a right triangle

The three given points are the vertices of a right triangle.

8 0
4 years ago
The third angle in an isosceles triangle is 32 more than 2 times as large as each of the two base angles. Find the measure of ea
DIA [1.3K]

Answer: the third angle is 106 degrees.

The base angles are 37 degrees each.

Step-by-step explanation:

In an isosceles triangle, the base angles are equal.

Let x represent the measure of each of the base angles.

The third angle in an isosceles triangle is 32 more than 2 times as large as each of the two base angles. It means that the measure of the third angle would be

(2x + 32) degrees

The sum of the angles inna triangle is 180 degrees. It means that

x + x + 2x + 32 = 180

4x = 180 - 32

4x = 148

x = 37

The third angle is

2x = 32 = (2 × 37) + 32

= 74 + 32 = 106

5 0
3 years ago
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