Question

What is the area of this figure? Please help

Answer 1

Answer:

Step-by-step explanation:

The square has 4 sides with length 4

The right triangle has the right side equal to 4yd + 4yd(from the square) = 8yd

Using the Pythagorean Theorem, we find that the left side of the triangle has length = 10yd

The area of the whole thing is the area of the square + the area of the triangle

The formula for the area of a square with sides l is $A_s = l^2$

The area of the triangle is trickier, but you can imagine tracing a line in the left side and the upper side to form a rectangle, and the area of that is A = $l * L$, the area of the triangle will be half the area of the rectangle so it'll be $A = \frac{6 * 8}{2} = 24 (yd)^{2}$

The total area will be;

Area of the square + Area of the triangle = $16 + 24 = 40 yd^{2}$