Answer:
The output of the function y = -6x + 8 when the input is x = 20 is -112.
Step-by-step explanation:
y = -6x + 8
Input the value x = 20.
y = -6(20) + 8
Multiply -6 and 20.
y = -120 + 8
Add -120 and 8.
y = -112.
45 times the numerator plus the denominator is most likely going to equal the same amount as if it were doubled.
Answer:
x = 5
Step-by-step explanation:
<u>__________________________________________________________</u>
<u>FACTS TO KNOW BEFORE SOLVING</u> :-
- In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. :
⇒
[∵ Bases are equal on both the sides]
<u>__________________________________________________________</u>

Lets express it in terms of 2.




Here the bases on both the sides are equal. Hence ,



Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=
/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL =
/2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN
<span>3x − y = 2
y = 3x - 2
x + y = 6
x + 3x - 2 = 6
4x - 2 = 6
4x = 6 + 2
4x = 8
x = </span>

x = 2
Hence, the x co-ordinate is 2.