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Alex Ar [27]
4 years ago
7

Math Help Please and Thank You!

Mathematics
1 answer:
guapka [62]4 years ago
5 0
The answer is A=28.26
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Identify the zeros of f(x)= (x-7)(x+4)(3x-2) Choices:
Kobotan [32]

Answer:

second option

Step-by-step explanation:

Given

f(x) = (x - 7)(x + 4)(3x - 2)

To find the zeros let f(x) = 0, that is

(x - 7)(x + 4)(3x - 2) = 0

Equate each factor to zero and solve for x

x - 7 = 0 ⇒ x = 7

x + 4 = 0 ⇒ x = - 4

3x - 2 = 0 ⇒ 3x = 2 ⇒ x = \frac{2}{3}

zeros are x = - 4, x = \frac{2}{3}, x = 7

7 0
3 years ago
What is the value of y in the solution to the following system of equations? 5x − 3y = −11 2x − 6y = −14 −1 0 1 2
Alekssandra [29.7K]
5x - 3y = -11 (×2)
2x - 6y = -14 (x5)

10x - 6y = -22
10x - 30y = -70
---------------------- -
24y = 48
y = 2
5 0
3 years ago
1.What are the zeros of the polynomial function?
Lorico [155]
Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
_______________

Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________


To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9


Well, this would be your answers.


7 0
4 years ago
Two cyclist leave towns 75moles apart at the same time and travel towards each other. One cyclist travels 7 mph faster than the
GaryK [48]

Answer:

Step-by-step explanation:

Givens

d1 = d

d2 = 75 - d

r1 = x

r2 = x + 7

t = 3

Equation

x*t + (x + 7)*t = 75

This equation represents the total distance travelled. Neither one of the cyclists have gone 75 miles, but they both have gone distances that equal a total of 75 miles.

Solution

3x + (x + 7)*3 = 75

3x + 3x + 21 = 75

6x + 21 = 75

6x = 54

6x/6 = 54/6

x = 9

Answer

The first cyclist is going 9 miles / hr

The second cyclist is going 16 miles / hour

5 0
3 years ago
Read 2 more answers
Find the circumference of a circle with a diameter of 13 feet
svetoff [14.1K]

Answer:

Step-by-step explanation:

radius=diameter/2

13/2

6.5

circumference of a circle=2πr

=2*3.14*6.5

=40.82 feet

=

5 0
3 years ago
Read 2 more answers
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