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3 years ago

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Which of the following does not represent this number? 45.701

1 answer:

dolphi86 [110]3 years ago

5 0

I can't see the following you miss of didn't pin it I think....

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$6,000 dollars is invested in two different accounts earning 3% and 5% interest. at the end of one year, the two accounts earned

Anettt [7]

<u>Answer-</u>

<em>$2000</em><em> were invested at 5%</em>

<u>Solution-</u>

Let x amount of money was invested at 5% and (6000-x) amount was invested as 3%

We know that,

$i=\dfrac{P\cdot r\cdot t}{100}$

Putting the values,

$i_1=\dfrac{P_1\cdot r_1\cdot t}{100}$

$i_1=\dfrac{x\cdot 5\cdot 1}{100}=\dfrac{5x}{100}$

And

$i_2=\dfrac{P_2\cdot r_2\cdot t}{100}$

$i_2=\dfrac{(6000-x)\cdot 3\cdot 1}{100}=\dfrac{3(6000-x)}{100}$

According to the question,

$\Rightarrow \dfrac{5x}{100}+\dfrac{3(6000-x)}{100}=220$

$\Rightarrow \dfrac{5x+3(6000-x)}{100}=220$

$\Rightarrow 5x+3(6000-x)=22000$

$\Rightarrow 5x+18000-3x=22000$

$\Rightarrow 5x-3x=22000-18000$

$\Rightarrow 2x=4000$

$\Rightarrow x=2000$

Therefore, $2000 were invested at 5%

8 0

3 years ago

Read 2 more answers

A simple random sample of 20 days in which Parsnip ate seeds was selected, and the mean amount of time it took him to eat the se

bearhunter [10]

Answer:

$(14.5-13.9) -1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = -1.63$

$(14.5-13.9) +1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = 2.83$

And the confidence interval for this case $-1.63 \leq \mu_1 -\mu_2 \leq 2.83$

Step-by-step explanation:

We know the following info from the problem

$\bar X_1 = 14.5$ sample mean for the group 1

$s_1 = 3.98$ the standard deviation for the group 1

$n_1= 20$ the sample size for group 1

$\bar X_2 = 13.9$ sample mean for the group 2

$s_1 = 4.03$ the standard deviation for the group 2

$n_2= 17$ the sample size for group 2

We have all the conditions satisifed since we have random samples.

We want to construct a confidence interval for the true difference of means and the correct formula for this case is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

The degrees of freedom are given :

$df = n_1 +n_2- 2 = 20+17-2=35$

The confidence level is 0.9 or 90% and the significance level is $\alpha=1-0.9=0.1$ and $\alpha/2 = 0.05$ and the critical value for this case is:

$t_{\alpha/2} = 1.69$

And replacing the info given we got:

$(14.5-13.9) -1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = -1.63$

$(14.5-13.9) +1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = 2.83$

And the confidence interval for this case $-1.63 \leq \mu_1 -\mu_2 \leq 2.83$

5 0

2 years ago

Solve for x and explain?

zhannawk [14.2K]

Answer:

x = 7

Step-by-step explanation:

When 2 secants are drawn from an external point to a circle.

The product of the external part and the entire secant of one secant is equal to the product of the external part and the entire secant of the other secant, that is

5(5 + x) = 6(6 + 4) ← distribute and simplify both sides

25 + 5x = 6 × 10

25 + 5x = 60 ( subtract 25 from both sides )

5x = 35 ( divide both sides by 5 )

x = 7

4 0

3 years ago

If there are 2,000 females and 2,000 males enrolled at a college and four different students are randomly selected to receive a

DENIUS [597]

Answer:

500

Step-by-step explanation:

you just divide 2000 by 4 and get 500

6 0

2 years ago

What is 8 thousandths less than 4.989?

emmainna [20.7K]

8000-4.989 so when you see the word less than it means that you have to subtract and more than you have to add so the answer for this question will be 7,995.011

8 0

2 years ago