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3 years ago

Use the equations c = 100 - d and c = 20 +d to model the equation. Solve the system using substitution

1 answer:

6 0

You can substitute 20 + d for c in the first equation which gives you

20+ d = 100 - d then solve
2d = 80
d= 40
then put the value for d back into one of the original equations
c= 20 + d
c = 20 + (40)
c = 60

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What shows 29,000 in scientific notation ?

Bogdan [553]

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3 years ago

Determine the domain of the function

skelet666 [1.2K]

Answer:

Option B is correct.

The domain of the function h(x) is: $\{x | x\neq \pm 6 , x\neq 0\}$

Step-by-step explanation:

Domain states that the complete set of all the possible values of the independent variable where function is defined.

Given the function:

$h(x) = \frac{9x}{x(x^2-36)}$

To find the excluded value in the domain of the function.

equate the denominator to 0 and solve for x.

i.e

$x(x^2-36) = 0$

⇒x = 0 and $x^2-36 = 0$

⇒x = 0 and $x^2 = 36$

x = 0 and $x = \pm 6$

So, the domain of the function h(x) is the set of all real number except x = 0 and $x = \pm 6$

Therefore, the domain of the function h(x) is:

$\{x | x\neq \pm 6 , x\neq 0\}$

8 0

4 years ago

Read 2 more answers

Please help me thank you

mezya [45]

Answer:

d=14.5

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4 0

3 years ago

Equation in slope intercept form of the line that passes through the given points of (2,-5) and (-8,3)

Reika [66]

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3 years ago

Read 2 more answers

The lengths of nails produced in a factory are normally distributed with a mean of 3.34 centimeters and a standard deviation of

Shtirlitz [24]

Answer:

3.47 and 3.21

Step-by-step explanation:

Let us assume the nails length be X

$X \sim N(3.34,0.07^2)$

Value let separated the top 3% is T and for bottom it would be B

$P(X < T)= 0.97$

Now converting, we get

$P(Z < \frac{T-3.34}{0.07})= 0.97$

Based on the normal standard tables, we get

$P(Z < 1.881)= 0.97$

Now compare these two above equations

$\frac{T-3.34}{0.07} = 1.881 \\\\ T = 1.881 \times 0.07 + 3.34 \\\\ = 3.47$

So for top 3% it is 3.47

Now for bottom we applied the same method as shown above

$P(Z < \frac{B-3.34}{0.07})= 0.03$

Based on the normal standard tables, we get

$P(Z < -1.881)= 0.03$

Now compare these two above equations

$\frac{B-3.34}{0.07} = -1.881$

$= -1.881 \times 0.07 + 3.34 \\\\ = 3.21$

hence, for bottom it would be 3.21

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3 years ago