All categories

2 years ago

Some whole numbers are irrational numbers? True or False?

Mathematics

2 answers:

Mariulka [41]2 years ago

7 0

Answer:

False. Whole numbers are actually Rational Numbers.

I hope that helps u!!!

Semenov [28]2 years ago

7 0

The answer is False.

You might be interested in

KM=<br> Help me asap pleasee

Rina8888 [55]

Answer: 3

Step-by-step explanation:

By the intersecting chords theorem,

$(KM)(16)=(4)(12)\\\\KM=3$

8 0

2 years ago

Jacqueline reach the end of the trail in two hours and 15 minutes. Write the amount of hours he spent on the trail as a mixed nu

LenaWriter [7]

You would keep the 2 hour for the whole number of the mixed number and then, make the minutes (15) as a fraction with 60, and divide them both by 20. that is just for the mixed number.

4 0

3 years ago

Review the steps of the proof of the identity

astraxan [27]

Answer:

step 2

and then step 3 : the error neutralized the error of step 2

Step-by-step explanation:

sin(a + b) = sin(a)cos(b) + cos(a)sin(b)

and because

sin(-b) = -sin(b)

cos(-b) = cos(b)

we have

sin(a - b) = sin(a)cos(-b) + cos(a)sin(-b) =

= sin(a)cos(b) - cos(a)sin(b)

3pi/2 = 270° or -90°.

sin(3pi/2) = sin(270) = sin(-90) = -1

that means, it is the full radius straight down from the center of the circle.

cos(3pi/2) = cos(270) = cos(-90) = cos(90) = 0

so, step 1 is correct :

sin(A - 3pi/2) = sin(A)cos(3pi/2) - cos(A)sin(3pi/2) =

= sin(A)×0 - cos(A)×(-1) (correct step 2)

but as we see, the provided step 2 is incorrect.

it should have been the indicated

sin(A)×0 - cos(A)×(-1)

and NOT the provided

sin(A)×0 + cos(A)×(-1)

step 3 based on the erroneous step 2 should then have been

sin(A)×0 - (1)cos(A)

but instead another error with the sign was made that neutralized the error of step 2 and we got after this second mistake by pure chance the overall correct step 3

sin(A)×0 + (1)cos(A)

so, again, the first error was made in step 2.

but technically, there was also a consecutive error made in step 3 to bring everything back to the correct approach.

4 0

2 years ago

Help me on this one please !

Semenov [28]

Look at my work below I plugged it in multiple times and tried plugging in A. D is the only answer that is probable

6 0

3 years ago

Which of the following functions has a period of 8 π ?

KengaRu [80]

<h3>Answer: Choice B</h3>

Explanation:

The general template of a sine function is

y = Asin(B(x-C))+D

The value of B is the only thing that determines the period T. We ignore every other term.

It turns out that T = 2pi/B which can be solved to B = 2pi/T

Plug in the given period of T = 8pi and compute to get

B = 2pi/T

B = (2pi)/(8pi)

B = 2/8

B = 1/4

This means that the term out front of the x is 1/4 and the equation must be $y = \sin\left(\frac{1}{4}x\right)$ which matches with answer choice B.

4 0

2 years ago