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Zarrin [17]
3 years ago
11

√2 times √800 anyone know?

Mathematics
1 answer:
jeka943 years ago
5 0

\sqrt{2}  \times  \sqrt{800}

\sqrt{2}  \times 20 \sqrt{2}

\sqrt{2}  \times  \sqrt{2}  =  \sqrt{4}  \:  = 2

20 \times 2 = 40

therefore \:  \:  \:  \sqrt{2}  \times  \sqrt{800} = 40
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Angle 1 and angle 2 form a linear pair.if m angle =5x+9 and m angle 2=3x+11,find the measures of both angels.
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Answer: ∠1 = 109°    ∠2 = 71°

<u>Step-by-step explanation:</u>

If the two angles form a linear pair, then their sum is 180°

  ∠1      +     ∠2     = 180°

(5x + 9) + (3x + 11) = 180

              8x + 20  = 180

              8x          = 160

                x          = 20

∠1 = 5x + 9

    = 5(20) + 9

    = 100   + 9

    = 109

∠2 = 3x + 11

     = 3(20) + 11

     =    60  + 11

     =         71

  <u> CHECK:</u>

∠1   + ∠2 = 180°

109° + 71° = 180°

     180°   = 180°  \checkmark

7 0
3 years ago
Paisley works on her drawings for 2 hours. She spends 1/6 hour on each drawing. How many drawings does she work on in 2 hours? H
sertanlavr [38]

Answer:

1/12

Step-by-step explanation:

1/6 divided by 2 = 1/12

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If we list all the possible factors (in order) of 12, we get 1, 2, 3, 4, 6, 12. This is the case because 1 x 12, 2 x 6, and 3 x
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1, 2, 3, 5, 6, 10, 15 and 30.

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