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4 years ago

State a true conclusion. 1) All rabbits like lettuce. 2) My pet is a rabbit. Conclusion:

Mathematics

2 answers:

mojhsa [17]4 years ago

8 0

I think it would be: "My pet rabbit likes lettuce."

il63 [147K]4 years ago

5 0

I believe it would be 2) my pet is a rabbit.

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Find the value of x.

VMariaS [17]

$\huge{ \bold{ \bigstar \: pythagoras \bigstar}}$

Pythagoras :

${10}^{2} = {x}^{2} + {x}^{2}$

$100 = 2{x}^{2}$

$100 \div 2 = {x}^{2}$

$50 = {x}^{2}$

$x = \sqrt{50}$

$x = \sqrt{25 \times 2}$

$\red{x = 5 \sqrt{2} }$

3 0

3 years ago

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What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

Step(i):-

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

step(ii):-

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

step(iii):-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

Conclusion:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

5 0

3 years ago

PLEASE HELP ASAP!!

QveST [7]

Answer:

The radius of the circle is 3.5 inches.

Step-by-step explanation:

The radius is half the diameter:R= 1/2 d

Substitute the value of d (7 inches) in the formula to find r:

r= 1/2 x 7 in

r= 3.5 in

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3 years ago

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Quadrilateral CDEF is reflected across the x-axis and translated 3 units left to create quadrilateral GHJK. http://prntscr.com/i

eimsori [14]

To answer this question, you will reflect the original shape to make a new trapezoid at K(2, -1), G (2, -4), H(6, -4), and J (6, -2). You will keep the y value in each ordered pair and write the opposite x value to show the reflection.

These are all then translated 3 units left to create the new ordered pairs:

K(-1, -1), G(-1, -4), H(3, -4), J(3, -2)

The two parallel sides are KG and JH. These were originally CF and DE.

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4 years ago

The point V(2, 3) is translated 8 units left. What are the coordinates of the resulting point,

Nostrana [21]

V(-6,3)

subtract 8 from 2, since it is moving to the left but keep the y the same since it is not translated up or down

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3 years ago