What is the answer to 9*20^15-23/5

Find the arc length of AB⌢. Round your answer to the nearest hundredth.

gizmo_the_mogwai [7]

Answer:

3.14 ft

Step-by-step explanation:

The arc AB is the minor arc of the given circle. The length l of the minor arc of a circle is given as

l = Ф°/360° × 2πr

where

Ф is the angle of the arc at the center of the circle

r is the radius of the circle and

π is a mathematical constant equivalent to 22/7

r = 8/2 = 4 ft

Hence

l = 45°/360° × 2 × 22/7 × 4

= 22/7 ft

= 3.14 ft

5 0

3 years ago

A high school guidance counselor determined the following information regarding students and their likelihood of playing a sport

iogann1982 [59]

Conditional Probability

Given two events A and B (not excluding), the probability that A occurs given that B has occurred is called a <em>conditional probability</em> and is calculated as:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Where P(A∩B) is the probability that A and B occur simultaneously and P(B) is the probability that B occurs.

Now with the given data, we must find the values of the required probabilities.

30% of the students play a sport (S), this means that:

70% of the students don't play a sport (NS).

65% of the students have a job.

Note that there could be students who both play sports and have a job.

Of the 30% of the students who play a sport, 50% have a job. This means that:

15% of the students play a sport and don't have a job

15% of the students play a sport AND have a job

65% - 15% = 50% of the students have a job and don't play a sport

That last number is the numerator of the equation given above:

P(A∩B) = 0.5

The event B corresponds to students that don't play a sport (NS), thus:

P(B) = 0.7

Thus we have:

$P(A|B)=\frac{0.5}{0.7}=\frac{5}{7}$

The required probability is 5/7 or 0.7143

4 0

1 year ago

The daily sales at a convenience store produce a normal distribution with a mean of $1,250 and a standard deviation of $125. The

timama [110]

Answer:

0.6844 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $1,250

Standard Deviation, σ = $125

We are given that the distribution of daily sales is a bell like shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find

P(sales less than $1,310)

$P( x < 1310) = P( z < \displaystyle\frac{1310 - 1250}{125}) = P(z < 0.48)$

Calculation the value from standard normal z table, we have,

$P(x < 1310) =0.6844= 68.44\%$

0.6844 is the probability that sales on a given day at this store are less than $1,310.

4 0

3 years ago

1. A factory worker in Cambodia makes 320,000 Cambodian Riels per month. If 1 U.S. dollar equals 4000 Cambodian Riels, how much

Mama L [17]

1. A factory worker in Cambodia makes 320,000 Cambodian Riels per month. If 1 U.S. dollar equals 4000 Cambodian Riels, how much does the factory worker make in U.S. in dollars per year?
For this case we must first take the amount $ per month.
We have then:
1 $ ---> 4000
x = ----> 320000
Solving for x we have
x = (320000/4000) * (1) = $ 80 / month
We have then that 1 year two 12 months
($ 80 / month) * (12 months / 1 year) = $ 960 / year
Answer
the factory worker make 960 U.S. in dollars per year

2. People in Japan on average eat 3 ounces of fish per day. How many pounds of fish is this per week?

For this case, the first thing you should know is that a week has 7 days.
We can make a rule of three to find the number of ounces per week
3 ---> 1
x = ----> 7
x = (7/1) * (3) = 21ounces / week
Then, we should do the conversion of ounces to pounds
1 oz = 0.0625 pounds
Thus,
(21ounces / week) * (0.0625 punds / 1 ounce) = 1.3125 pounds / week
answer
3 ounces of fish per day is 1.3125 pounds / week

3. The town of Lloró, Colombia has an average yearly rainfall of 500 inches. On average, how many centimeters of rain does the town get each day?

The first thing you should know in this case are the following conversions:
1 year = 365 days
1 inch = 2.54 centimeters
We have the annual average rainfall is
500 (inches / year)
Making the conversion we have
500 (inches / year) * (2.54) (centimeters / inches) * (1/365) (year / days) =
3.45 (centimeters / days)
Answer
the town get each day 3.45 (centimeters / days)

4. The average American student is in class for 330 min / day. How many hours / day is this? Part b) How many sec / day?
The first thing you should know for this case are the following conversions
1 hour = 60 minutes
1 minute = 60 seconds.
Making the right conversions we have
330 (min / day) * (1/60) (hour / minutes) = 5.5hours / day
On the other hand we have
330 (min / day) * (60/1) (seconds / minutes) = 19800 sec / day
answer
330 (min / day) = 5.5hours / day
330 (min / day) = 19800 sec / day

7 0

3 years ago

which statements are true? check all that apply. the line x = 0 is perpendicular to the line y = –3. all lines that are parallel

CaHeK987 [17]

1) True that line x = 0 is perpedicular to y = -3. Because x = 0 is parallel to the y-axis and y = -3 is parallel to the x-axis.

2) True that all the lines that are parallel to the y-axis are vertucal lines (the y-axis is vertical)

3) False that all lines perpendicular to the x-axis have a slope o 0. Their slope trends to infinity.

4) False that the equation of the line parallel to the x-axis that passes through the point (2, –6) is x = 2. The right equation is y = - 6

5) True thath the equation of the line perpendicular to the y-axis that passes through the point (–5, 1) is y = 1

4 0

3 years ago

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