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3 years ago

Anyone one have the answer to this

Mathematics

1 answer:

OLEGan [10]3 years ago

4 0

Answer: A. y= 5x(x-2)

Step-by-step explanation:

To begin with, this graph has two X values, making it a parabola

Parabola's are NOT linear.

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Random variables X Poisson~ ( a) ,Y Poisson ~ ( a) . X and Y are independent. If 2 1, 2 1. U =2X+ Y-1, V=2X- Y +1. Find: ) Cov (

german

By definition of covariance,

$\mathrm{Cov}(U,V)=E[(U-E[U])(V-E[V])]=E[UV-E[U]V-UE[V]+E[U]E[V]]=E[UV]-E[U]E[V]$

Since $U=2X+Y-1$ and $V=2X-Y+1$ , we have

$E[U]=2E[X]+E[Y]-1$

$E[V]=2E[X]-E[Y]+1$

$\implies E[U]E[V]=(2E[X]+E[Y]-1)(2E[X]-(E[Y]-1))=4E[X]^2-(E[Y]-1)^2=4E[X]^2-E[Y]^2+2E[Y]-1$

and

$UV=(2X+Y-1)(2X-(Y-1))=4X^2-(Y-1)^2=4X^2-Y^2+2Y-1$

$\implies E[UV]=4E[X^2]-E[Y^2]+2E[Y]-1$

Putting everything together, we have

$\mathrm{Cov}(U,V)=(4E[X^2]-E[Y^2]+2E[Y]-1)-(4E[X]^2-E[Y]^2+2E[Y]-1)$

$\mathrm{Cov}(U,V)=4(E[X^2]-E[X]^2)-(E[Y^2]-E[Y]^2)$

$\mathrm{Cov}(U,V)=4V[X]-V[Y]=4a-a=\boxed{3a}$

7 0

4 years ago

What theorem or postulate proves the two triangles congruent?

Sav [38]

the theorem is SAS that proves the two triangles are congruent

5 0

3 years ago

Read 2 more answers

Can someone help me to find length CD

uysha [10]

Answer:

CD = 3.602019190339

Step-by-step explanation:

CD = DA - CA

DA = DB×Cos(29) = 18.7×cos(29) = 16.355388523507

BA = BA×cos(43) = 18.7×cos(43) = 13.676314220278

CA = BA÷tan(47) = 13.676314220278÷tan(47) = 12.753369333168

Then

CD = 16.355388523507 - 12.753369333168 = 3.602019190339

7 0

4 years ago

How many weeks are in 5 years

Gnoma [55]

- -- There are 260.714 weeks total in 5 years.

But you can round by doing this:

52*5=260

This is because you have 52 weeks in a year and 55 years so you multiply.

6 0

3 years ago

Read 2 more answers

Plot the two decimals on the number line below 0.43, 0.39. Write an inequality comparing the two decimals. Explain your answer u

Ilya [14]

Answer:

See the image below.

Step-by-step explanation:

The decimals 0.43 and 0.39 are equivalent to 43/100 and 39/100. These decimals lie between 0 and 1.

Draw a number line, mark off and label the multiples of 0.10(e.g 0.10, 0.20) in the interval 0-1.

Mark 0.43 between 0.4 and 0.5, a little closer to 0.4.

Mark 0.39 between 0.3 and 0.4, just behind 0.4.

Since 0.39 is smaller than 0.43( 0.39 lies on the left to 0.43), the inequality is:

0.39<0.43

5 0

4 years ago