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3 years ago

What is –36° converted to radians?

Mathematics

1 answer:

Stells [14]3 years ago

4 0

let's recall that there are 180° in π radians, thus

$\bf \begin{array}{ccll} degrees&radians\\ \cline{1-2} 180&\pi \\ -36&x \end{array}\implies \cfrac{180}{-36}=\cfrac{\pi }{x}\implies -5=\cfrac{\pi }{x}\implies x=\cfrac{\pi }{-5}\implies x=-\cfrac{\pi }{5}$

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The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

2 years ago

Which number produces a rational number when you multiplied by 0.5

strojnjashka [21]

2

Hope I helped!

Let me know if you need anything else!

<span>~ Zoe (Rank:'Genius')</span>

8 0

3 years ago

Applicants who wish to be admitted to a certain professional school in a large university are required to take a screening test

Elden [556K]

Answer:

Probability of eligible applicants who pass the exam is 0.665

probability of applicants who are ineligible but pass the exam 0.063

Step-by-step explanation:

Total percentage eligible applicants who pass the exam

$\textrm {89\% of 70\%}= \dfrac{89\times70}{100}=62.3\%$

Total ineligible applicants who pass the exam

$\textrm {14\% of 30\%}= \dfrac{14\times30}{100}=4.2\%$

All applicants who pass this exam 62.3% + 4.2% = 66.5%

Probability of applicants who pass the exam

$\textrm{probability }= \dfrac{66.5}{100}=0.665$

Out of 66.5% applicants who pass the exam , 4.2% applicants are ineligible

$\textrm{so the probability is}\dfrac{4.2}{66.5}=0.063$

Probability of applicants who pass the exam is 0.665

probability of applicants who are ineligible but pass the exam 0.063

6 0

2 years ago

Please check my question. 11 points. thanks for the help.

n200080 [17]

Its right.................

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2 years ago

Four horses are pulling a wagon. Each horse drinks 45000 ml of water each day. How many liters of water will the horses drink in

s2008m [1.1K]

45000 x 4 = 180,000

180,000 * 5 = 900,000 ml in 5 days

1 liter = 1000 ml

900,000 / 1000 = 900 liters of water

3 0

3 years ago