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Amanda [17]
4 years ago
13

James received a grant for his classroom to buy new computers, which weigh 12 ounces. He is going to buy 24 of them and use a cr

ate that can handle up to 20 pounds. How many pounds are left before the crate is at its maximum limit?
Mathematics
2 answers:
Alenkinab [10]4 years ago
8 0

Answer:

2 pounds

Step-by-step explanation:

If james has to buy 24 new computers that weigh 12 ounces using a crate that can handle 20 pounds we can determine how many pounds left before the crate is at its maximum. We have to convert the ounces into pounds through conversion

The conversion factor from ounces to pounds is:

16 ounces = 1 pounds

We can conver 12 ounces by dividing by 16:

=12/16=3/4

Therefore 12 ounces is 3/4 pounds.

If he buys 24 computers weighing at 3/4 pounds each we can determine the total weight of the 24 computers:

=24*(3/4)=72/4=18

The total weight of 24 computers is 18 pounds and if the crate can take a maximum 20 pounds, there is:

=20-18=2

2 pounds left before the crate is at its maximum.

insens350 [35]4 years ago
4 0
Two pounds will be left before the crate reaches its minimum limit.
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In ΔJKL, the measure of ∠L=90°, JL = 24, LK = 7, and KJ = 25. What is the value of the sine of ∠K to the nearest hundredth?
podryga [215]

<u>Given</u>:

Given that JKL is a right triangle.

The measure of ∠L is 90°

The length of JL = 24, LK = 7, and KJ = 25.

We need to determine the value of sine of ∠K.

<u>Value of sin ∠K:</u>

The value of sin ∠K can be determine using the trigonometric ratio.

Thus, we have;

sin \ \theta=\frac{opp}{hyp}

Substituting \theta=K, the side opposite to angle K is JL and the hypotenuse is JK

Thus, we have;

sin \ K=\frac{JL}{JK}

Substituting JL = 24 and JK = 25, we get;

sin \ K=\frac{24}{25}

Simplifying, we get;

sin \ K=0.96

     K=sin^{-1}(0.96)

     K=73.74^{\circ}

Thus, the measure of sine of ∠K is 73.74°

6 0
4 years ago
A rectangle is twice as long as it is wide. If its length and width are both
puteri [66]

Answer:

a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle

Step-by-step explanation:

Let l = the original length of the original rectangle

Let w = the original width of the original rectangle

From the description of the problem, we can construct the following two equations

l=2*w (Equation #1)

(l+4)*(w+4)=l*w+88 (Equation #2)

Substitute equation #1 into equation #2

(2w+4)*(w+4)=(2w*w)+88

2w^2+4w+8w+16=2w^2+88

collect like terms on the same side of the equation

2w^2+2w^2 +12w+16-88=0

4w^2+12w-72=0

Since 4 is afactor of each term, divide both sides of the equation by 4

w^2+3w-18=0

The quadratic equation can be factored into (w+6)*(w-3)=0

Therefore w=-6 or w=3

w=-6 can be rejected because the length of a rectangle can't be negative so

w=3 and from equation #1 l=2*w=2*3=6

I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.

5 0
3 years ago
Help me write an explanation
Zigmanuir [339]

Answer:

9.375 grams

Step-by-step explanation:

30 days = 3(10 days)

m = 75·0.5³ = 9.375 grams

4 0
3 years ago
Find the missing side length in the image attached.
Aleks [24]

Answer:

? = 56.

Step-by-step explanation:

In the problem, the side 20 corresponds to side 32 and side 20 + 35 corresponds to side 32 + ?.

\frac{20}{32} =\frac{20 + 35}{? + 32}

\frac{5}{8} =\frac{55}{? + 32}

\frac{1}{8}=\frac{11}{? + 32}

? + 32 = 8 * 11

? + 32 = 88

? = 56.

Hope this helps!

8 0
3 years ago
Read 2 more answers
HELP HELLP HELP MEH I NEED 16 MORE CLASSES LEFT FOR SCHOOL LET IT BECOME 15 PLEASE
vodomira [7]

Answer:

2*2*9+4*12*3=36+144=180

Step-by-step explanation:

8 0
4 years ago
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