Question

A bakery sells 7196 donuts in 2010. The bakery sells 9236 donuts in 2015. Write a linear model that represents the number y of donuts that the bakery sells x years after 2010

Answer 1

Answer:

$y=408x+7196$

Step-by-step explanation:

x is number of years after 2010

y is number of donuts

we are given

A bakery sells 7196 donuts in 2010

So, when x=0 , y=7196

Let's assume

$x_1=0,y_1=7196$

The bakery sells 9236 donuts in 2015

$x_2=5,y_1=9236$

now, we can find slope

$m=\frac{y_2-y_1}{x_2-x_1}$

we can plug values

$m=\frac{9236-7196}{5-0}$

$m=408$

now, we can use point slope form of line

$y-y_1=m(x-x_1)$

we can plug values

$y-7196=408(x-0)$

$y-7196=408(x-0)$

$y=408x+7196$