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vivado [14]
3 years ago
10

How do I solve x over 6 + 4+15 ?

Mathematics
2 answers:
amm18123 years ago
4 0
X/6 + 4 = 15

First, subtract 4 to both sides:

x/6 = 11

Now multiply 6 to both sides:

x = 66
yanalaym [24]3 years ago
3 0
x/6+4=15 \\ x/10=15 \\ *10\ \ \ *10 \\ x=150
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How does doubling the base effect the perimeter of the triangle
Contact [7]

i think it will make it smaller due to the base being longer which stretches out the two sides and makes less space inside of the triangle

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3 years ago
PLZ ANSWER ASAP A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without r
LUCKY_DIMON [66]

Answer:

10/25

10+9+6 equals 25 and there is 10 red marbles. I think this is the answer don't take my word for it.

8 0
2 years ago
Read 2 more answers
Find the distance and midpoint for the points (5,5) and (1,2).
stealth61 [152]

Answer:

midpoint = (3,3.5)

distance = 5

Step-by-step explanation:

midpoint = (x1+X2/2, y2+y2/2)

=(5+1/2, 5+2/2)

=(6/2, 7/2)

=(3, 3.5)

distance= √(x2-x1)^2 -(y2-y1)^2

=√(1-5)^2 -(2-5)^2

= √ 16+9 =√25 =5

5 0
2 years ago
Jose bought 3 pens and 6 pencils for $6.60. Amy bought 5 pens and 8 pencils for $10.00. How much does one pencil cost?
xenn [34]

Answer:

pen = $1.20,  pencil = $0.50

Step-by-step explanation:

let x = pen

let y = pencil

create system of equations:

3x + 6y = 6.60        [can be simplified to be x + 2y = 2.20]

5x + 8y = 10.00

substitution method:

x = 2.2 - 2y

5(2.2 - 2y) + 8y = 10

11 - 10y + 8y = 10

-2y = -1

y = 1/2

solve for 'x':

3x + 6(1/2) = 6.6

3x + 3 = 6.6

3x = 3.6

x = 1.2

7 0
2 years ago
Find the distance between each pair of points.<br> 3) (6, -2), (8, -3)<br> 4) (7,-8), (-8, 2)
castortr0y [4]

Answer:

3) \sqrt{5}

4)5\sqrt{13}

Step-by-step explanation:

distance between two points:

d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}

we have:

3) (6, -2), (8, -3)

x_{1} = 6

y_{1} =-2

x_{2} = 8

y_{2} =-3

so we have:

d =\sqrt{(8-6)^{2}+ (-3-(-2))^{2}}\\\\d =\sqrt{(2)^{2}+ (-1)^{2}}\\\\d = \sqrt{4+ 1}\\\\d=\sqrt{5}

4) (7,-8), (-8, 2)

x_{1} = 7

y_{1} =-8

x_{2} =-8

y_{2} =2

d =\sqrt{(-8-7)^{2}+ (2-(-8))^{2}}\\\\d =\sqrt{(-15)^{2}+ (10)^{2}}\\\\d = \sqrt{225+ 100}\\\\d=\sqrt{325}\\\\d=5\sqrt{13}

3 0
3 years ago
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