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4 years ago

How do I solve x over 6 + 4+15 ?

Mathematics

2 answers:

amm18124 years ago

4 0

X/6 + 4 = 15

First, subtract 4 to both sides:

x/6 = 11

Now multiply 6 to both sides:

x = 66

yanalaym [24]4 years ago

3 0

$x/6+4=15 \\ x/10=15 \\ *10\ \ \ *10 \\ x=150$

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Ber [7]

Refer to this previous solution set

brainly.com/question/26114608

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Problem 4

Like the three earlier problems, we'll place the kicker at the origin and have her kick to the right. The two roots in this case are x = 0 and x = 20 to represent when the ball is on the ground.

This leads to the factors x and x-20 and the equation $y = ax(x-20)$

We'll plug in (x,y) = (10,28) which is the vertex point. The 10 is the midpoint of 0 and 20 mentioned earlier.

Let's solve for 'a'.

$y = ax(x-20)\\\\28 = a*10(10-20)\\\\28 = -100a\\\\a = -\frac{28}{100}\\\\a = -\frac{7}{25}\\\\$

This then leads us to:

$y = ax(x-20)\\\\y = -\frac{7}{25}x(x-20)\\\\y = -\frac{7}{25}x*x-\frac{7}{25}x*(-20)\\\\y = -\frac{7}{25}x^2+\frac{28}{5}x\\\\$

The equation is in the form $y = ax^2+bx+c$ with $a = -\frac{7}{25}, \ b = \frac{28}{5}, \ c = 0$

The graph is below in blue.

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Problem 5

The same set up applies as before.

This time we have the roots x = 0 and x = 100 to lead to the factors x and x-100. We have the equation $y = ax(x-100)$

We'll use the vertex point (50,12) to find 'a'.

$y = ax(x-100)\\\\12 = a*50(50-100)\\\\12 = -2500a\\\\a = -\frac{12}{2500}\\\\a = -\frac{3}{625}\\\\$

Then we can find the standard form

$y = ax(x-100)\\\\y = -\frac{3}{625}x(x-100)\\\\y = -\frac{3}{625}x*x-\frac{3}{625}x*(-100)\\\\y = -\frac{3}{625}x^2+\frac{12}{25}x\\\\$

The graph is below in red.

4 0

3 years ago

A random number is selected from the interval [6.35, 10]. Find the probability that the number is within a distance of 0.25 from

exis [7]

Let X be a random number selected from the interval. Then the probability density for the random variable X is

$f_X(x)=\begin{cases}\dfrac1{10-6.35}=\dfrac1{3.65}\approx0.2740&\text{if }6.35\le x\le 10\\0&\text{otherwise}\end{cases}$

8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute

P(|X - 8| < 0.25) + P(|X - 10| < 0.25)

… = P(7.75 < X < 8.25) + P(9.75 < X < 10.25)

… = P(7.75 < X < 8.25) + P(9.75 < X < 10)

(since P(X > 10) = 0)

… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)

… = 0.2055

6 0

3 years ago

There are 80 picnic tables at the park. During the first weekend of the summer, there were 40 available tables. During the secon

Aleksandr [31]

Answer:

Step-by-step explanation:

We can see a pattern of 1/2 as the week progresses. 1/2 of 80 is 40, 1/2 of 40 is 20, 1/2 of 20 is 10, so for the fourth week 1/2 of 10 is 5.

8 0

4 years ago

Will give brainliest for correct answer

Romashka [77]

Answer:

A. 240/7

Step-by-step explanation:

10^4x/24 * 10^3x/24 = 10^10

10^7x/24 = 10^10

7x/24 = 10

x = 240/7

6 0

3 years ago

According to the rational root theron what are all the potential roots of f(x)=9x^4-2x^2-3x+4

Viefleur [7K]

Answer:

Potential roots: $\frac{9}{4},\frac{9}{2},9,\frac{3}{4},\frac{3}{2},3, \frac{1}{4},\frac{1}{2},1$

Step-by-step explanation:

Simply put, the rational roots theorem tells us that if there are any rational roots of a polynomial function, they must be in the form

± $\frac{FactorsOfa_{0}}{FactorsOfa_n}$

Where

a_n is the number before the highest power of the polynomial, and

a_0 is the constant in the polynomial

From the polynomial shown, we have a_n = 9 and a_0 = 4

The factors of 9 are 9, 3, 1

and

The factors of 4 are 4,2,1

So, if there are any rational roots, they would be:

± $\frac{FactorsOfa_{0}}{FactorsOfa_n}$

± $\frac{9,3,1}{4,2,1}$

Which is ± 9/4, 9/2, 9/1, 3/4, 3/2, 3/1, 1/4, 1/2, 1/1

$\frac{9}{4},\frac{9}{2},9,\frac{3}{4},\frac{3}{2},3, \frac{1}{4},\frac{1}{2},1$

5 0

3 years ago