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vivado [14]
3 years ago
10

How do I solve x over 6 + 4+15 ?

Mathematics
2 answers:
amm18123 years ago
4 0
X/6 + 4 = 15

First, subtract 4 to both sides:

x/6 = 11

Now multiply 6 to both sides:

x = 66
yanalaym [24]3 years ago
3 0
x/6+4=15 \\ x/10=15 \\ *10\ \ \ *10 \\ x=150
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Nastasia [14]

Hello from MrBillDoesMath!

Answer:

See Discussion section below

Discussion:

2x^2 + 5x + 3  = (2x+3)(x+1) which is Choice 3


3x^2+10x+4  =-1/3 (-3 x + sqrt(13) - 5) (3 x + sqrt(13) + 5)

I don't think any of the provided choices are right!


8x^2+10x-3 = (2x+3)(4x-1) which is Choice 2


6x^2-7x-4 = -1/24 (-12 x + sqrt(145) + 7) (12 x + sqrt(145) - 7)

I don't think any of the provided choices are right!


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4 0
3 years ago
If the width of something is 5m and the perimeter is 22m, what is the length and area
Nadusha1986 [10]
I assume that this 'something' has a rectangular shape. If its width is 5m, than the length of two sides is 2 * 5 = 10m. Now if the perimeter is 22 square meters, then the lenght of another two sides is 12 / 2 = 6.

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4 0
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A first number plus twice a second number is 9. Twice the first number plus the second totals 21. Find the numbers
WITCHER [35]
Let x and y be the numbers;
We have x + 2y = 9 and 2x + y = 21;
Then, x = 9 - 2y;
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7 0
3 years ago
Evaluate the function f(x) at the given numbers (correct to six decimal places).
statuscvo [17]

Answer:

The values of given function are shown in the below table.

Step-by-step explanation:

The given function is

f(x)=\frac{x^2-5x}{x^2-x-20}

Simplify the given function.

f(x)=\frac{x(x-5)}{x^2-5x+4x-20}

f(x)=\frac{x(x-5)}{x(x-5)+4(x-5)}

f(x)=\frac{x(x-5)}{(x+4)(x-5)}

Cancel out the common factor.

f(x)=\frac{x}{x+4}

Substitute x=5.5 in the above equation.

f(5.5)=\frac{5.5}{5.5+4}

f(5.5)=\frac{5.5}{9.5}

f(5.5)=0.57894736842

f(5.5)\approx 0.578947

Similarly find the value for all values of x.

The values of given function are shown in the below table.

8 0
3 years ago
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