Question

The equations of three lines are given below.

Answer 1

Step-by-step explanation:

Hey there!

Here, The equations are;

-3y=5x+6

5x+3y+6=0.........(i)

10x-6y+4 =0......(ii)

y= -3/5x+3.......(iii)

From equation (i).

$slope(m1) = \frac{ - coeff. \: ofx}{coeff. \: of \: y}$

Put all values.

$m1 = \frac{ - 5}{3}$

Now, from equation (ii).

$m2 = \frac{ - coeff. \: of \: x}{coeff. \: of \: y}$

Put all values.

$m2 = \frac{ - 10 }{ - 6}$

$m2 = \frac{5}{3}$

As m1 is not equal to m2 it is not parallel lines.

For perpendicular lines;

m1×m2= -1.

$\frac{ - 5}{3} \times \frac{5}{3}$

After simplifying it we get -25/9 which is not equal to-1. So, it is not perpendicular lines.

Therefore, the lines are neither parallel nor perpendicular.

But the lines of equation (ii) and (iii) are perpendicular to eachother.

-3/5×5/3= -1

[ so, the line (ii) and (iii) are perpendicular to eachother but others are neither]

Hope it helps...

Answer 2

Answer:

line 1&2 are neither

line 1&3 are also neither

lines 2 and 3 however are perpendicular since they make 90 degree angles when they meet.

Step-by-step explanation: